Have you ever wondered how scientists decide the “zero point” for measuring the electrical potential of all electrodes? The answer is Standard Hydrogen Electrode (SHE). SHE serves as the reference with an assigned potential of exactly 0.00 V. The SHE’s standardized conditions (1 M H⁺, 1 atm $\mathrm{H}_2$, 25°C) ensure accurate and consistent measurements of electrode potentials, which are essential for reliable electrochemical experiments and industrial processes. The SHE is used as a reference electrode in pH meters, providing a stable reference for measuring the voltage difference and determining the pH of solutions.
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A hydrogen electrode in which the pressure of hydrogen gas is maintained at 1 atm and the concentration of H+ ions in the solution is 1M, is called a standard hydrogen electrode (SHE).
SHE half reaction Electrode potential
$\mathrm{H}_2 \rightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-} 0.0 \mathrm{~V}$ (Anode)
$2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2 0.0 \mathrm{~V}$ (Cathode)
A hydrogen electrode in which the pressure of hydrogen gas is maintained at 1 atm and the concentration of H+ ions in the solution is 1M, is called a standard hydrogen electrode (SHE).
SHE half reaction Electrode potential
$\mathrm{H}_2 \rightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-} 0.0 \mathrm{~V}$ (Anode)
$2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2 0.0 \mathrm{~V}$ (Cathode)
This equation gives the relationship between electrode potential and the concentration of ions in the solution. In other words, it shows the dependency of electrode potential on the concentration of the ions with which the electrode is reversible.
For a single electrode involving the reduction process,
$\mathrm{Mn}^{+}+\mathrm{ne}^{-} \rightarrow \mathrm{M}(\mathrm{s})$
The reaction quotient Q is defined as aM[M
⇒$\mathrm{E}=\mathrm{E}^{\circ}-\frac{\mathrm{RT}}{\mathrm{nF}} \ln Q$
This is the Nernst equation which helps us to calculate the non-standard EMF of any Half cell. It can be extended to full of any half cell. It can be extended to full cell which we will be learning later.
Now, at 25∘C or 298 K
$\begin{aligned} & E=E^{\circ}-\frac{2.303 \times 8.314 \times 298}{n \times 96500} \log _{10} \frac{[M]}{\left[M^{n+}\right]} \\ & E=E^{\circ}-\frac{0.059}{n} \log _{10} \frac{[M]}{\left[M^{n+}\right]}\end{aligned}$
Here $\mathbf{R}=$ Gas constant
$\mathrm{T}=$ Absolute temperature
$\mathrm{E}^{\circ}=$ Standard Emf of the cell
E = Electrode potential of cell
F = Faraday number
$\mathbf{n}=$ number of electrons transferred
$
\mathrm{xA}+\mathrm{yB} \xrightarrow{\mathrm{ne}^{-}} \mathrm{mC}+\mathrm{nD}
$
The emf can be calculated as
$
\text { Ecell }=\mathrm{E}^{\mathrm{o}} \text { cell }-\frac{0.059}{\mathrm{n}} \log \frac{[\mathrm{C}]^{\mathrm{m}}[\mathrm{D}]^{\mathrm{n}}}{[\mathrm{~A}]^x[\mathrm{~B}]^{\mathrm{y}}}
$
In using the above equation, the following facts should be kept in mind.
The Standard Hydrogen Electrode (SHE) is a reference electrode used in electrochemical measurements. Its applications and significance are.
1. Reference Electrode for Measuring Electrode Potential
2. Electrochemical Series
3. pH Measurement
4. Corrosion Studies
5. Electrolysis and Industrial Processes
Example.1
1. Consider the following cell with hydrogen electrodes at different pressures p1 and p2.
$\mathrm{Pt}, \mathrm{H}_2\left(p_1\right)\left|\begin{array}{c}\mathrm{H}^{+}(\mathrm{aq}) \\ 1 \mathrm{M}\end{array}\right| \mathrm{H}_2\left(p_2\right), \mathrm{Pt}$
The EMF of the cell is given by:
1) $\frac{\mathrm{RT}}{\mathrm{F}} \ln \frac{\mathrm{p}_1}{\mathrm{p}_2}$
2) (correct) $\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\mathrm{p}_1}{\mathrm{p}_2}$
3) $\frac{\mathrm{RT}}{\mathrm{F}} \ln \frac{\mathrm{p}_2}{\mathrm{p}_1}$
4)$\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\mathrm{p}_2}{\mathrm{p}_1}$
Solution
For the given concentration cell, the Nernst equation can be written as
$\begin{aligned} \mathrm{E}_{\text {cell }} & =0.059\left[\mathrm{pH}_{\mathrm{a}}-\mathrm{pH}_{\mathrm{c}}+\frac{1}{2} \log \frac{\left(\mathrm{pH}_2\right)_{\mathrm{a}}}{\left(\mathrm{pH}_2\right)_{\mathrm{c}}}\right] \\ & =0.059\left[0-0+\frac{1}{2} \log \frac{p_1}{p_2}\right] \\ & =\frac{0.059}{2} \log \frac{p_1}{p_2}=\frac{R T}{2 F} \ln \frac{p_1}{p_2}\end{aligned}$
Hence, the answer is the option (2).
Example.2
2. A hydrogen electrode placed in a solution containing sodium acetate and acetic acid in the ratio of x: y and y : x has an electrode potential value E1 and E2 volts respectively at 25oC. The pKa value of acetic acid is:
1) (correct) $\frac{-\left(E_1+E_2\right)}{2 \times 0.059}$
2) $\frac{\left(E_1+E_2\right)}{2 \times 0.059}$
3) $\frac{E_2-E_1}{2 \times 0.059}$
4) $\frac{-\left(E_1+E_2\right)}{0.059}$
Solution
The reaction occurring in the hydrogen electrode is given below:
$\mathrm{H}^{+}+\mathrm{e}^{-} \longrightarrow \frac{1}{2} \mathrm{H}_2$
Using the Nernst Equation, the electrode potential can be written as
$\mathrm{E}=-0.059 \log \frac{1}{\left[\mathrm{H}^{+}\right]}=-0.059 \mathrm{pH}$
In the two given cases, the Hydrogen ions are obtained by buffer solution having the ratio of Salt : Acid as $\mathrm{x}: \mathrm{y}$ and $\mathrm{y}: \mathrm{x}$
The pH of an acidic buffer can be calculated as
$\begin{aligned} & \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \left(\frac{\text { Salt }}{\text { Acid }}\right) \\ & \therefore \mathrm{pH}_1=\mathrm{pK}_{\mathrm{a}}+\log \frac{\mathrm{x}}{\mathrm{y}}\end{aligned}$
Similarly,
$\mathrm{pH}_2=\mathrm{pK}_{\mathrm{a}}+\log \frac{\mathrm{y}}{\mathrm{x}}$
Thus, the respective electrode potentials can be written as
$\begin{aligned} \therefore \mathrm{E}_1 & =-0.059 \mathrm{pH}_1 \\ \mathrm{E}_2 & =-0.059 \mathrm{pH}_2\end{aligned}$
pH2=pKa+logyr
Now, adding the two potentials gives us
$\begin{aligned} & \left(\mathrm{E}_1+\mathrm{E}_2\right)=-0.059\left(\mathrm{pK}_{\mathrm{a}}+\log \frac{\mathrm{x}}{\mathrm{y}}\right)-0.059\left(\mathrm{pK}_{\mathrm{a}}+\log \frac{\mathrm{y}}{\mathrm{x}}\right) \\ & \left(\mathrm{E}_1+\mathrm{E}_2\right)=-0.059 \times 2 \times \mathrm{pKa} \\ & \mathrm{pK}_{\mathrm{a}}=\frac{-\left(\mathrm{E}_1+\mathrm{E}_2\right)}{2 \times 0.059}\end{aligned}$
Hence, the answer is the option (1).
Example.3
3. Select the correct statement out of the following.
1) The absolute value of potential is defined.
2) (correct) The Potential of SHE is arbitrarily assigned zero value.
3)In SHE, the pH of the solution is 7
4)In SHE, the pressure of H2 (g) is 760atm.
Solution
The absolute value of the potential is not defined. We can only measure the potential difference. As a convention, the SHE is assigned a value of zero, and the potential of other species is measured concerning the SHE.
Hence, the answer is option (2).
Example 4
The standard reduction potential of Hydrogen is zero because
1) (correct)It is taken as a standard reference.
2)It is the easiest to oxidize.
3)It has a single electron.
4)It is electronegative
Solution
The absolute electric potential for an electrode cannot be measured without forming a cell. Therefore, hydrogen is taken as a standard reference and its potential is taken as zero.
Hence, the answer is option (1).
The Standard Hydrogen Electrode was developed to provide a consistent and reliable reference point for measuring electrode potentials, which is essential for standardizing electrochemical measurements, understanding reaction dynamics, and advancing scientific and industrial applications in electrochemistry.
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