Pt Deen Dayal Mahavidyalaya, Ladampura All Questions

Hello Vansh

You can appear for the On- Demand Examination System. Eligibility Criteria to appear for the Sr. Secondary exams is the minimum age of the student to take admission in the Senior Secondary Course is 15 years as on 31st January 2019 (born on or before 31/01/2004)
And, the learner must have passed the Secondary course from a recognised Board.

Check the details - https://sdmis.nios.ac.in/

Prospectus- https://d39vpsp5tn2021.cloudfront.net/static/dist/images/pdf/academic_prospectus.pdf

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Eligibility Criteria for admission to B.Arch programme through JEE Main exam is

Candidate should have studied Physics, Chemistry and Mathematics mandatorily in 10+2 or equivalent exam and Candidates are required to have secured minimum 50% marks in these subjects in aggregate and 50% individually too.

Do let us know if you have any other query.

Good Luck!

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HELLO ! RISHIN

With this score it will be difficult to get good architecture colleges as 85.55 is too low percentile for NITs and SPAs.You can take rough idea about your rank using this formula,Probable rank={100-percentile score}*145386/100.This will gives you rank under general quota.Your rank will be aound 21k.To get NITs and SPAs your rank must be under 2k.Don't worry ,you still have one atttempt for JEE mains paper 2019.

You can ask if you have any other queries.

GOOD LUCK!

Hello Aspirant,

  As of now it is not possible to tell you either you will qualify for a particular college or not. It will be possible only after the final cutoff release by officials. But we can help in calculating your probable General rank after this exam which is around 32,130. With this rank you can get college in your home state. It is highly unlikely for you to get NITs. To get more information about previous year cutoffs of various colleges for B.arch and B.plan courses, you can visit the following link:

 https://engineering.careers360.com/articles/jee-main-paper-2-result

Good Luck !!!!

• Rank Formula = (100 - your total score) X 145386 /100.
• Your expected rank is 9566 by using above formula

Hello 

The thing is Doing in the NIT's is very good and also the particular person should have the required skills and good knowledge the b.arch branch is also good but the competition is also high but from the college side they provide the very best companies so overall hardwork should be done by the particular person whoever is studying in NIT

Good luck

Hello

Since his percentile score in the exam is very low, he can prepare for the exam again and appear for JEE Main April exam with full preparation as best of the two scores will be considered. As he has scored well in Mathematics, he need to focus more on the other subjects (Aptitude test and Drawing Test).

He can join any crash course and also solving previous year question papers and sample papers will help a lot.

Do let us know if you have any other query.

Good Luck!

• Rank Formula = (100 - your total score) X 145386 /100.
• Your expected rank is 2427 by using above formula

• https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

Hello sir

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile or NTA score.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.For more colleges visit https://engineering.careers360.com/jee-main-college-predictor  .Hope this helps.

Good Luck