Hi there,

Let E1 and E2 respectively denote the events that a red ball is transferred from a bag 1 to 2 and a green ball is transferred from bag 1 to bag 2

P(E1)=4/6

P(E2)=2/6

LET A be the event that the ball drawn is green

(i) when a red ball is transferred from bag 1 to 2

P(A/E1)=5/9

2) when a green ball is transferred from bag 1 to 2

P(A/E2)=6/9

P(E2)/A= p(E2) p(A/E2)/ p(E1) p(A/E1) + p(E2)p(A/E2)

=3/8

Hope it helps you

Good luck!

Hello Gautam,

Let us consider A1 is the events that a red ball is transferred from a bag I to Bag II and  A2 Event is that green ball is transferred from the bag I to Bag II.

P(A1) = 4/6 & P(A2) = 2/6

Assume B be the event that the ball drawn from Bag is Green.

(1) when a Green ball is transferred.

P(B/A1) = 6/9

(2) when a Red ball is transferred.

P(B/A2) = 5/9

Now, P(A2/B) = [P(B/A2) × P(A2)] ÷ [(P(A1) × P(B/A2)) + (P(A2) × P(B/A1)]

Similarly, P(A2/B) = [((2/6) × (6/9)) ÷ ((4/6) × (5/9)) + ((2/6) × (6/9))]

= 3/8

Probability that the ball drawn fromBag I to Bag II is 3/8.

Hope this information was useful to you.

Good Luck!!

Hello candidate,

The moral of the Moon written by Robert Manish regarding the paper bag princess is: The Paper Bag Princess is about being resourceful to solve our problems, being courageous to go after what we want and also about knowing when to walk away. Hope you found it helpful.

If you have any other doubts regarding any educational topics feel free to post it here.

Dear aspirant hope you are doing well. Seems your question is incomplete or important information is missing from your question. As you not mentioned your university/ college name, so it is difficult to say about anything. So I request you to provide proper information. So I can help you.

Thank you

Dear aspirant.

Hope you are doing well. You have not mentioned the university or college name.without these basic information it is difficult to say anything. Seems your question is incomplete or important information is missing from your question. So I request you to repost your question, so I can help you in  a better way..

Thank you

Hello,

IGNOU BAG 1st, 2nd, and 3rd year Exam Schedule 2021

The test will be held in December 2021 at the University. The IGNOU University will provide a pdf version of the December Term End Exam Date Sheet. Now, let's talk about the students who will be taking the exam. They may then use the internet approach to check IGNOU BAG Online Date Sheet.

IGNOU Examination Form Dates 2021

For information related to IGNOU

IGNOU Date Sheet 2021 (Revised) - December TEE Term End Exam Dates (careers360.com)

Hope this helps.

Hello Sourav,

I would suggest you to use your OJEE rank card as you do have a better ranking there and being from Orrisa you have good chances of getting government colleges there. The colleges you have good chances of getting are:

• College of Engineering and Technology, Biju Patnaik University of Technology
• VSSUT - Veer Surendra Sai University of Technology
• Parala Maharaja Engineering College
• Government College of Engineering
• Central Institute of Plastics Engineering and Technology

Good luck, Hope it helps!!

Hello aspirant,

Hope you are fine and healthy.

As your JEE Mains rank for SC category is 61252 which is not very promising.

I would suggest that you should go with OJEE SC rank 123 which is quite impressive and have a chance to get government institutions.

Here is a list of colleges where you can try for admission,

=> Institute of Management and Information Technology, Cuttack

=> Government College of Engineering, Kalahandi

=> Government College of Engineering, Keonjhar

=> Parala Maharaja Engineering College, Behampur

Here is a link, where you can get more information regarding engineering colleges which take admission through OJEE counselling,

https://engineering.careers360.com/colleges/ranking/top-engineering-colleges-in-India-accepting-ojee-score

Hope it helps you..

Best of luck..

Bag A=(4R+5B) balls

⇒ Bag B=(3R+6B) balls

⇒ Probability of red form bag A and black from bag B =

9

4

×

10

6

=

90

24

⇒ Probability of red from bag B and black from bag A =

10

3

×

9

5

=

90

15

⇒ P(balls of different colours)=P( red from bag A and black from bag B)+P( red from bag B and black from bag A)

=

90

26

+

90

15

=

90

41

All the best student,

Hope this helps you.