Bio Engineering
Question : Select the option that can be used as a one-word substitute for the given group of words. Words written on a tombstone in the memory of the person who has died
Option 1: epilogue
Option 2: epitaph
Option 3: stela
Option 4: prologue
Correct Answer: epitaph
Solution : The second option is the correct choice.
An epitaph specifically refers to the words or inscriptions written on a tombstone or a grave marker in memory of the person who has died. It serves as a brief statement honouring the deceased.
The meanings of other options are as follows:
Therefore, the correct answer is epitaph.
Hello,
Here's a list of 10 top MBA biotechnology colleges in Bangalore:
1) Indian Institute of Science (IISc)
2) Institute of Bioinformatics and Applied Biotechnology (IBAB)
3) Acharya Institute of Technology
4) Dayananda Sagar Institutions
5) M.S. Ramaiah University of Applied Sciences
6) Christ University
7) PES University
8) Alliance University
9) Jain University
10) Kristu Jayanti College
Hope this helps you,
Thank you
Question : Directions: In a certain code language, towards the main gate is written as nt zb ps cq, and main purpose of this is written as rq kl bt zb. How is main written in the given language?
Option 1: ps
Option 2: kl
Option 3: rq
Option 4: zb
Correct Answer: zb
Solution : Given: 1. towards the main gate ⇒ nt zb ps cq 2. main purpose of this ⇒ rq kl bt zb
By comparing all the above-coded sentences, we find that – The common word and the code in the given sentences are main and zb.
So, main will be coded as zb. Hence, the fourth option is correct.
Question : Pipe A can fill an empty tank in 30 hours and B can fill it in 10 hours. Due to a leakage in the tank, it takes pipes A and B together 1.5 hours more to fill completely than it would have otherwise taken. What is the time taken by the leakage alone to empty the same tank completely, starting when the tank is completely full?
Option 1: 42 hours
Option 2: 40 hours
Option 3: 36 hours
Option 4: 45 hours
Correct Answer: 45 hours
Solution : Time taken by pipe A to fill a tank = 30 hours Part of tank filled by pipe A in an hour = $\frac{1}{30}$ Time taken by pipe B to fill a tank = 10 hours Part of tank filled by pipe B in an hour = $\frac{1}{10}$ Part of the tank filled by pipes A and B together in an hour $=\frac{1}{30}+\frac{1}{10}=\frac{1+3}{30} = \frac{2}{15}$ Time taken by pipes A and B together to fill the tank = $\frac{15}{2}$ = 7.5 hours Let $x$ be the time taken by the leakage to empty the tank. Part of tank emptied by the leakage in an hour = $\frac{1}{x}$ Time taken by pipes A and B together to fill the tank along with the leakage = 7.5 + 1.5 = 9 hours Part of the tank filled by pipes A and B along with the leakage = $\frac{1}{9}$ So, $\frac{1}{30}+\frac{1}{10}-\frac{1}{x} = \frac{1}{9}$ ⇒ $\frac{1}{x} = (\frac{1+3}{30}) - \frac{1}{9} $ $= \frac{12-10}{90}$ $= \frac{2}{90}$ $= \frac{1}{45}$ $\therefore x = 45$ Hence, the correct answer is 45 hours.
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