All Questions

Chemistry - Class 11

Follow
Showing 1 - 10 out of 34 Questions
146 Views

A mixture of CO and CO2 is found to have a density of 1.5g/l at 30C and 730 torr.what is the composition of the mixture?

piyush263001 7th Aug, 2022

Hello,


You should first know how to proceed for the solution. From the Ideal Gas equation -

.           P V  = n R T

.           P V  = ( given mass / Avg Molar Mass ) R T

.           P = ( d R T ) / Avg. Molar Mass


Let the average molecular mass be M

M = ( d R T ) / P

= ( 1.5×0.0821×303×760 ) / 730  ( Use proper Units)

= 38.85


------- Let x mole of CO and (1−x) mole of CO 2 be present


x×28+(1−x)×44=38.85

x=0.3218


Mole % of CO=32.18 and

Mole % of CO 2 =100−32.18=67.82


I hope you find the answer helpful.

Thank you.

34 Views

an unknown gas mass 12g(moler mass=120g)is kept in a close vessel at 1 atm and t C.if he increase temperature by 10 C.P rises by 10%.find t- a.100C b.127C c.173C d.-173C

piyush263001 7th Aug, 2022

Hello,


From the Ideal Gas equation,


P V = n R T = ( given mass, w / molar mass, m ) R T


1 × V = ( 12 / 120 ) × R × (273+t)    ----- (i)


1.1 × V=  ( 12 / 120 ) × R × ( 273 + t + 10 ). ----- (ii)


Dividing equation (ii) by equation (i), we get


1.1 = (273+t+10) / ( 273+t+)

or  t = −173 degree Celsius


I hope you find the answer helpful.

Thank you.

1756 Views

12 g mg reacts with dilute mineral acid to produce maximum hydrogen equal to

LALBEE 19th May, 2022

Hello Aspirant,

Hope you are doing great. When the 12g Mg reacts with dilute mineral acid to produce maximum hydrogen equal to 0.5 ml. You can calculate as through the No. of Moles of Mg= Moles of H2 and there for the no. of moles of Mg= 12/24 which is equal to 0.5ml. And you can even calculate any other reaction with the same procedure.

ALL THE BEST

182 Views

What is best app for Chemistry all formula briefly for class 11, 12 neet , iit jee??

thakurvishesh1 8th Jul, 2022

If you are looking for the notes of Chemistry, Physics or Mathematics for JEE Main and Advanced, then you should definitely look for Career 360's own JEE tutoring platform which is learn Career 360. Here you can give many tests and strengthen your preparation for JEE Main and Advanced and emerge victorious.

Hope I have answered your question. All the best!

3739 Views

I am in class 11 preparing for JEE 2023. What are the prerequisites for studying chemical kinetics, chemical equilibrium and ionic equilibrium in chemistry?

Ayush Maurya 23rd Dec, 2021

Hello aspirant

Good to see that your preparing for JEE and I hope you can qualify it to. Now Coming to your question I want to tell you some major domains in which you have to excel to start your ionic or chemical equilibrium chemical kinetics.

You should study these things before that:

  1. Make clear your thermodynamics concepts.
  2. Acids bases and salts which you must have read are also important.
  3. For ionic if you know the concepts of logarithms then you can do calculations very easily.
  4. Two major things you must have excel in it that are mole concept and concentration terms.

Now for chemical kinetics you would be getting it very easily if you clear it firstly.

Hope it helps!

Thank you!

95 Views

what is sublimation experiment

Ankita Singh 11th Dec, 2021

Hello,

Sublimation is the transition of a substance from a solid to a gas state without passing through a liquid state. When a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid, is achieved, sublimation occurs. The reverse of sublimation, in which a substance changes from a gas to a solid state, is called deposition or desublimation.

Thank you!

82 Views

Y chromosome is less active why

Preetam Bhowmik 5th Dec, 2021

Dear Aspirant, since Y-chromosome possesses small amount of euchromatin that contains DNA or genes, therefore it is genetically less active. Recent research has shown that the Y chromosome has developed some pretty convincing mechanisms to "put the brakes on", slowing the rate of gene loss to a possible standstill. I hope you are clear now. If you have any other doubts feel free to ask. All The Best!!!

137 Views

how to study n remember inorganic for neet?i cannot predict trends inspite of doing basic chaps,all mcqs getting incorrect...

Anushri Varshney 13th Jul, 2021

Greetings of the day dear candidate!

Inorganic chemistry is indeed the most difficult yet easy for some people due to its easy understanding of chapters but no doubt the questions that came from these portions are a bit tricky. Also, the issue of forgetting the reaction and compound names are a bit difficult. No need to worry about this as it is common among many students. The NEET is going to be held on 12th September 2021.

So, I would suggest you follow these steps for 3-4 weeks, If it works for you I would be very grateful.

  • Try to start your day with the Inorganic chemistry portion.
  • Revise the concepts of compounds and characteristics along with trends.
  • Make some short notes of each unit that consist most important topic especially the reactions and naming.
  • Try to learn the compound by drawing their shapes. It will help you in realizing more.
  • Daily revise one unit and solve questions accordingly. After that analyze where you are lagging.

Also, do not forget to make flashcards as they will be very helpful in last-minute revision.

Prepare well and maintain your health.

Wishing you very good luck :)

50 Views

how to calcualate the electron number in 1 mol?

Ayush 7th Jul, 2021

Hello candidate,

It's Very simple to calculate the electron number in 1 mole of any particle and you do it by- multiplying the charge on one electron (1.602 x 10^-19) with the Avogadro's number (6.022 x 10^23), which means that the charge of 1 mol ≈ 96500 C.

Hope you found it informational!!

IF you have any further queries, feel free to post it here!!


The question have been saved in answer later, you can access it from your profile anytime. Access now

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

Careers360 App
150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books