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What is College rank in Bengaluru

Nikita shahi 1st Aug, 2025

Hello,

Bengaluru is home to many top-ranked colleges and universities, especially for engineering, management, and science. Some of the highest-ranking colleges include:

  • Indian Institute of Science (IISc)  ranked among the top in India and globally for science & research.
  • RV College of Engineering (RVCE) it is  one of the top private engineering colleges in Karnataka.
  • BMS College of Engineering, MS Ramaiah Institute of Technology, and Christ University also rank high in different streams.

College ranks depend on factors like placements, faculty, infrastructure, and student reviews. You can check official rankings like NIRF or India Today rankings for updated information.

Thank you!


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SOME STUDENTS ARE SAYING THAT THE 47 LPA PACKAGE ARE NOT ON CMAPUS BUT THEY ARE OFF CAMPUS IS IT TRUE ??

Rajesh Reddy 1st Aug, 2025

Yes, the 47 LPA package might have been either off-campus based placement or through pre-placement offer (PPO) and not the college's on-campus drive. A lot of institutions put off-campus offers in the highest amount  of packages. Always confirm placement reports to be clear.

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how much additional amount should pay if i get government seat in private colleges through kcet

Pradeepa P 23rd Jun, 2025

If you get a government quota seat in a private college through KCET, the tuition fee is subsidized by the Karnataka government. For most professional courses like engineering or medical, the annual tuition fee ranges from sixty-five thousand to ninety-five thousand rupees. For courses like BSc Nursing or allied health sciences, it may range from twenty thousand to forty thousand rupees per year. In addition to the tuition fee, private colleges may charge extra amounts for hostel facilities, which can be around forty thousand to eighty thousand rupees annually, and for lab, library, or development fees, which may be between five thousand to fifteen thousand rupees. University or exam-related fees may also be around three thousand to five thousand rupees.

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i got 96 percentile which is 2722 rank in aeee exam i wanted slab 1 in cse ai amritapuri can i get it

kumardurgesh1802 24th May, 2025

Hello there,

With a 96 percentile and rank 2722 in AEEE, you have a good chance of getting admission in Slab 1 for CSE with AI at Amritapuri campus of Amrita Vishwa Vidyapeetham.

Slab 1 usually requires higher ranks and has a higher fee structure. Admission depends on seat availability and final cutoff during counseling.

Make sure to participate actively in counseling, keep your documents ready, and be prepared for fee payment to confirm your seat.

Your rank and percentile put you in a strong position for admission in this branch at Amritapuri.


I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

24 Views

csab counseling application form

Tanya Gupta 24th Sep, 2024

Hello,

The CSAB (Central Seat Allocation Board) counseling application form is used for admission to NITs, IIITs, and GFTIs based on JEE Main ranks. The form is typically available after the conclusion of JoSAA counseling. To apply, visit the official CSAB website, fill out the form with necessary details, upload required documents, and pay the application fee. The process includes special rounds for seat allocation to vacant seats. Stay updated on deadlines via the official website.

Hope this helps you,

Thank you

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Question : A sum of INR 900 is divided into two parts such that the interest on the first part at 4% simple interest per annum and that on the other part at 2% simple interest per annum are equal. What is the interest accumulated on each part in a year?

Option 1: INR 18

Option 2: INR 6

Option 3: INR 12

Option 4: INR 20

Team Careers360 25th Jan, 2024

Correct Answer: INR 12


Solution : Total sum, $P$ = INR 900
The interest rate on the first part, $R_1$ = 4%
The interest rate on the second part, $R_2$ = 2%
Time, $n$ = 1 year
Let $x$ and $900-x$ be the two parts.
Simple interest, SI = $\frac{PnR}{100}$
Simple interest on the first part = simple interest on the second part
⇒ $\frac{x×4×1}{100} = \frac{(900-x)×2×1}{100}$
⇒ $4x = 1800-2x$
⇒ $6x=1800$
⇒ $x=300$
Simple interest in each part
= $\frac{x×4×1}{100}$
= $\frac{300×4×1}{100}$
= INR 12
Hence, the correct answer is INR 12.

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