Examination
Hello aspirant,
Hope you are doing absolutely great.
So with regard to your query, the phase 3 for the SRM university exam that is SRMJEE will be held on June 25th and 26th. The last date to submit the application for Phase 3 examination is 20 June 2022. The phase 2 exam got completed in the month of April itself. Further, the results for the Phase 3 exam will be announced in the month of July 2022.
SRMJEE is a graduate level online exam. After qualifying the exam you will be able to get into counselling and further into the undergraduate level course.
Eligibility:
To be eligible for this exam you need to complete your 10+2 with an aggregate of 50% marks. You can be from any board. The direct admission is also available for this university. However, you need to be a ranker to qualify from this category.
The syllabus for the exam includes all the topics from Physics, Chemistry, Mathematics from 10+2. The exam will have 125 questions and there is no negative marking to this, 1 mark will be given for each and every correct answer. You will also have 5 marks for English Language and 10 marks for Aptitude test.
Checkout the following link regarding the exam dates of SRMJEE: https://engineering.careers360.com/articles/srmjeee-exam-dates
Check the below link regarding the exam of SRMJEE 2022: https://engineering.careers360.com/exams/srmjeee
Hope it helps you,
Good luck, Thank you.
Hi
Do you have all the 3 subjects i. e physics chemistry and Biology/biotechnology in your Bsc chemistry?
-------------------------) If yes, then you need to select code 5 , as it is for those who have passed 1st year of graduation with all the three of physics chemistry and Biology/biotechnology .
-------------------------) If not then, your highest qualification with all the three subjects i. e physics chemistry and Biology/biotechnology remains your 10+2 and thus you need to choose the code 02.
For more about neet codes visit
https://medicine.careers360.com/articles/neet-qualification-codes
Here's a short brief of Neet codes :-
--------) Code 1 :- code 1 is for class 12th board 2022 examination appearing students with physics, chemistry, biology and English or have have already appeared but results are awaited i. e have not been declared.
--------) Code 2 :- code 2 is for all those who have passed their 10+2/higher /senior secondary/ Indian School Certificate Examination with physics, chemistry, biology/biotechnology and English
--------) Code 3 :- code 3 says it is for those passed their intermediate / pre- degree examination with physics, chemistry, biology/biotechnology and English ,your physics, chemistry and biology/biotechnology should also contain practical exam.
--------) Code 4 :- pre - medical degree with Physics, chemistry and biology/biotechnology after passing hsc i. e 10+2 or puc or equivalent.
--------) Code 5 :- code 5 is for all those who have passed 1 st year graduation with all the three of Physics, chemistry and biology/biotechnology
--------) Code 6 :- code 6 is for all those students who have passed BSc with at least any two of following subjects :-
>>>>Physics,
>>>>chemistry ,
>>>>biology/biotechnology
--------) Code 7 :- code 7 is for those who have passed their examination from foreign board which is equivalent of Indian 10+2 board.
For more about codes visit
>>>>>>>>>>> NEET 2022 examination important dates are given below:-
Application form release:- 6th April 2022
Last form filling date:- 6th May 2022 upto 11:50 pm
Last date to pay application fee :- 7th May 2022 upto 11:50 pm
NEET 2022 Examination date :- 17th july 2022
Application form filling process is provided below:-
----------------------------------) visit the official website of neet i. e neet.nta.nic.in and register yourself
----------------------------------) fill in your details in the application form
----------------------------------) upload your documents
----------------------------------) pay the application fee
----------------------------------) take a printout of the confirmation page
To get complete information about documents to be uploaded and application form filling process go through
https://medicine.careers360.com/articles/neet-application-form/amp
Thank you
Hope you are doing great.
So with regard to your query, generally as per the eligibility criteria of JEE mains 2022 a candidate should score more than 75% marks in their 12th standard or in case if your score is less than 75% then you must score top 20 percentile in the JEE exam, which means you need to score between 80 to 90 percentile.
As you have mentioned that you are going to score more than 95 percentile in Jee main then you will be eligible for NITs.
You can also the following link for the eligibility criteria of JEE mains: https://engineering.careers360.com/articles/jee-main-eligibility-criteria#:~:text=Any%20student%20who%20has%20passed,apply%20for%20the%20entrance%20exam.&text=Students%20can%20appear%20in%20the,attempts%20(April%20and%20May).
Hope this helps you,
Good luck, thank you :)
It doesn't matter even if you have done diploma in interior designing after bsc.
Your number of attempts in neet doesn't matter even when it comes to codes, so it really has nothing to do even if you are attempting NEET for the 1st time.
Did you have at least any two of physics chemistry and Biology/biotechnology in your bsc?
-----------------------) If yes, then you need to select code 6 as it is for all those students who have passed BSc with at least any two of following subjects :-
-----------------------) If not, then you need to select code 2 as in that case your highest qualification with all the three PCB subjects remains 10 + 2
-----------------------------) Code 1 :- code 1 is for class 12th board 2022 examination appearing students with physics, chemistry, biology and English or have have already appeared but results are awaited i. e have not been declared.
-----------------------------) Code 2 :- code 2 is for all those who have passed their 10+2/higher /senior secondary/ Indian School Certificate Examination with physics, chemistry, biology/biotechnology and English
-----------------------------) Code 3 :- code 3 says it is for those passed their intermediate / pre- degree examination with physics, chemistry, biology/biotechnology and English ,your physics, chemistry and biology/biotechnology should also contain practical exam.
-----------------------------) Code 4 :- pre - medical degree with Physics, chemistry and biology/biotechnology after passing hsc i. e 10+2 or puc or equivalent.
-----------------------------) Code 5 :- code 5 is for all those who have passed 1 st year 3 year graduation with all the three of Physics, chemistry and biology/biotechnology
-----------------------------) Code 6 :- code 6 is for all those students who have passed BSc with at least any two of following subjects :-
-----------------------------) Code 7 :- code 7 is for those who have passed their examination from foreign board which is equivalent of Indian 10+2 board.
Hello aspirant!
Hope you are doing great!
Yes, you will be allowed to appear for the examination with your spectacles even though you didn't apply them in your photograph. Although if you are somebody who prefers to wear glasses regularly, it is advised to get a photo of yourself clicked in glasses.
Good luck!
How to start preparation for CUCET:-
Hope you are doing well...!!!
1) Understand the CUET Exam
2) Explore the CUET Exam
3) Draw up a Time Table
4) Practice more and more
5) Try to solve the previous year's question papers and mock test
6) Remain Motivated
For more information, you can visit the following link:-
https://university.careers360.com/articles/cucet-eligibility-criteria
I hope this information helps you!
All the best:)
Hello
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Hope this will help.
Dear aspirant !
Hope you are doing great ! It is easy to get admit card even without registration number ,,go to their portal try to find the option 'forgot registration number" click on that give the details whatever they ask ,you will get otp on your registered mobile number ,copy paste it and you will get your registration number . Do the process Carefully it is easy ,no need to panic.
Hope it helps you !
Thanking you
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