Geometry

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Geometry

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3458 Views

Why the geometry of carbocation is planner??

Khushi 15th Jan, 2020

Hello!!

The orbitals of carbocations are generally sp2 hybridized so that the three full orbitals are arranged in a trigonal planar geometry about the carbon nucleus. The remaining p orbital is empty and will readily accept a pair of electrons from another atom.

Thanks

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55 Views

Is S k goyal good for coordinate geometry for JEE MAIN?

sumit ranjan 10th Jan, 2020

Hi dear hope you are doing really well. Aise goyal is a very good book of Arihant publications and have very good definitions of all the concepts. the book also consists of a good number of questions which will clear all all the doubts and will help us to practice a lot for the examination and strengthen our base. With the help of this book we will definitely score better in JEE mains. Hope this will help you good luck.

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668 Views

which is best book for vector and 3D geometry for JEE MAIN?

sumit ranjan 10th Jan, 2020

Hi dear hope you are doing well
First of all solved NCERT textbook and then after you can go for cengage publication.Arihant publication is also good.First cover all the concepts and then go for numerical problem. Hope this will help you good luck

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61 Views

from which part in cordinate geometry percent of question is more in jee mains

Aditi amrendra Student Expert 5th Jan, 2020

Hello,

Here's a weightage distribution of Coordinate Geometry in JEE mains :

Straight Lines - 5
Circles - 5
Conic Section - 6.67
3D Geometry - 6.67
Vectors - 3.33

I hope this helps.

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98 Views

if I solve cordinate geometry from NCERT can I able to solve JEE mains questions

Manidipa Kundu Student Expert 5th Jan, 2020

hi,

see ncert books will clear your basic concepts, remember jee main basically a mcq based entrance test and you need to solve the question by using short tricks. it will be better to solve mcq from arihant or tata mac graw hill books.

hope you may understand.

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1608 Views

Trace the conic? 8x^2+4xy+5y^2=24(x+y)

Avishek Dutta 29th Nov, 2019

ax^2+2hxy+by^2+2gx+2fy+c=0.
8x^2+4xy+5y^2-24x-24y=0
a=8,b=5,c=0,h=2,f=g=-12
D=abc+2fgh-af^2-bg^2-ch^2
=8*5*0+2*(-12)(-12)*2-8*(-12)^2-5*(-12)^2-0*2^2
=-1296
Now
If D=0

If h^2-ab > 0,the equation represents two distinct real lines.
If h^2-ab = 0,the equation represents parallel lines.
If h^2-ab < 0,the equation represents non-real lines.

If D is non zero

If h^2-ab>0,it represents a hyperbola and a rectangular hyperbola(a+b=0).
If h^2-ab=0,the equation represents a parabola.
If h^2-ab<0,the equation represents a circle(a=b, h= 0) or an ellipse(a not equal to b).(For a real ellipse,
D/(a+b)<0).
Here D is non zero and h^2-ab=2-58=-36.
And also a not equal to b.Hence it is an ellipse.
Also D/(a+b)<0.
It is a real ellipse.

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