Hello Aspirant,

Hope you are doing great. One of India's most difficult competitive entrance exams is NEET. To pass the NEET-UG exam, students must adhere to the proper schedule, advice, and tactics. This is a guide for those planning to take the NEET-UG in 2023. It is crucial to have prior knowledge of the subjects that are more crucial than others in terms of the exam while preparing for NEET. Although it is important to thoroughly review the entire syllabus, the list of crucial topics created using data from previous exam cycles will aid candidates in planning their preparation and help them establish clear goals.

ALL THE BEST

Rs Aggarwal Quantitative Aptitude book may not be that helpful and useful for National Defence Academy examination. This is because the rs Aggarwal Quantitative aptitude book is primarily made for mentioned below competitive and entrance examinations only:

1. Bank probationary officer
2. State Bank of India probationary officer
3. IBPS Examination
4. Reserve Bank of India examination
5. Master of Business Administration
6. Campus recruitment test
7. Railway recruitment board exams
8. Sub inspector of police
9. SSC combined premier league exam
10. hotel management

Read about NDA Preparation:

https://www.google.com/url?sa=t&source=web&rct=j&url=https://competition.careers360.com/articles/how-to-prepare-for-nda/amp&ved=2ahUKEwiVwsO_pL32AhVjzTgGHd86D8EQFnoECAoQAQ&usg=AOvVaw0wwp4rxhugkeGV6ha6NQ24

Hi Vishesh,

The entrance paper of St. Xaviers Kolkata for admissions to the Bachelor's in Management studies course has basic maths questions with a few of higher order which have a minute chance of occuring in the paper. Revising topics of mathematics from classes 6-10 standards would be good and solving sample papers and mocks to get a notch of how the actual paper pattern is.

For more inforamtion on the papper pattern you can visit- https://bschool.careers360.com/articles/st-xaviers-bms-exam-pattern

hope it helps,

Thanks.

Hello,

From the first case, we can conclude that the girls are placed as per the following :

_ _ U _ _ _ R or U _ _ _ R _ _

From the second condition and forth condition, we can conclude that the girls are placed as per the following:

T S U _ _ _ R

Now the placing positions of P, Q and V are to be determined.

As per the third condition, if S and Q interchange their place then they will get exactly one new neighbor. That means their another one neighbor will be the same. So, the position of Q will be such that S and Q will share a common neighbor. So, we can conclude that, the placing arrangement of girls is like:

T S U Q _ _ R

As, more conditions are not given to satisfy the positions of P and V, there are two possible placing arrangements:

T S U Q P V R

and

T S U Q V P R

Best Wishes

Hello Nitesh, Hope you are doing good and preparing hard for the exams you are preparing for. Coming Back to your questions the answer to this question is simple but logic needs to be applied here.

Here the question says sum of 30 integers is 150. Here average is means 150/30 i.e. 5.

Out of these 20 integers don't exceed 5. Let's take case where we imagine all numbers of these that is 20 numbers to be 5 . Since we have to maximise the average of these 20 numbers that's why we are taking 5. So total of these 20 numbers would be 20*5 i.e. 100 giving us the average to be 5.

Now the rest 10 numbers can be also taken as 5 giving sum of 50 fulfilling our required sum. So it shows that the average is same as we got from the 30 numbers in total.

So we got the answer that the maximum of those 20 numbers average can be 5.

Hope you understood the solution and wish you all the best for your preparation.

Determining Whether a Relation Represents a Function

A relation is a set of ordered pairs. The set of the first components of each ordered pair is called the domain and the set of the second components of each ordered pair is called the range. Consider the following set of ordered pairs. The first numbers in each pair are the first five natural numbers. The second number in each pair is twice that of the first.

\[\{(1, 2), (2, 4), (3, 6), (4, 8), (5, 10)\}\tag{1.1.1}\]

The domain is \(\{1, 2, 3, 4, 5\}\). The range is \(\{2, 4, 6, 8, 10\}\).

Note that each value in the domain is also known as an input value, or independent variable, and is often labeled with the lowercase letter \(x\). Each value in the range is also known as an output value, or dependent variable, and is often labeled lowercase letter \(y\).

A function \(f\) is a relation that assigns a single value in the range to each value in the domain. In other words, no x-values are repeated. For our example that relates the first five natural numbers to numbers double their values, this relation is a function because each element in the domain, {1, 2, 3, 4, 5}, is paired with exactly one element in the range, \(\{2, 4, 6, 8, 10\}\).

Now let’s consider the set of ordered pairs that relates the terms “even” and “odd” to the first five natural numbers. It would appear as

\[\mathrm{\{(odd, 1), (even, 2), (odd, 3), (even, 4), (odd, 5)\}} \tag{1.1.2}\]

Notice that each element in the domain, {even, odd} is not paired with exactly one element in the range, \(\{1, 2, 3, 4, 5\}\). For example, the term “odd” corresponds to three values from the domain, \(\{1, 3, 5\}\) and the term “even” corresponds to two values from the range, \(\{2, 4\}\). This violates the definition of a function, so this relation is not a function.

Feel free to ask me in the comment box if you are having any further doubts

hope you find it helpful

Good Luck!