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Trigonometry

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127 Views

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Ayush Pandey 26th Aug, 2020

Hello,

Use AM>=GM formula so as to solve your question

(4tanx+9cotx)/2>=√(4tanx9cotx)

(4tanx+9cotx)>=2√(4tanx9cotx)

(4tanx+9cotx)>=2√(4*9)

4tanx+9cotx>=12

Hope that helps;

65 Views

sigma varies from 1 to n sinthetai

Ayush 13th Dec, 2020

Hi Candidate,

The Question you have asked about the value of Sigma varies from 1 to n sin theta is incomplete and incorrect.

I would rather advise you to recheck your question and post it again, with the correct information and values making it meaningful and solvable.

Have a Good Day. Best of luck.

Hope that this answer helps you!!

74 Views

What is series in Trigonometry?

AA 12th Jul, 2020

Hi aspirant ,

Trigonometric functions  can be expanded in power series , which facilitates approximations of the functions in extreme cases. The angle x must be in radians.

Hope this help you

best of luck



532 Views

please tell should I solve cengage any book like trigonometry or algebra portion of it individually to make my concept stronger if I am in class 12 and wanted to make the portion of mine class 11 stronger for jee mains and advanced ?

Deepshikha Student Expert 7th Jun, 2020
Hey,
To ace JEE Mains and Advance which includes the syllabus of class 11 and 12 Physics,Chemistry and Mathematics, you need to make sure your NCERT Concepts are clear. To strengthen your weaker areas, you can refer to reference books and Cengage is a good publication to practice with. For trignometry, SL Loney is also good and for Algebra Dr SK Goyal Arihant Publication is good.
For detailed information about the important books of JEE Mains follow the link given below:
https://engineering.careers360.com/articles/best-books-for-jee-main
Hope this helps.
Good luck.
25 Views

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Hrisheekesh Singh 9th May, 2020

Hi student,

I am not able to understand what you are actually asking.

I an see tag that your question is about trigonometry or is a numerical of trigonometry.

Please ask your full and clear question in the Comments section and I will be happy to help you out.

Good Luck!

1089 Views

how many days required to complete mechanics, Modern physics, Physical chemistry, organic chemistry, inorganic chemistry, algebra, calculus, trigonometry, 2d and 3d geometry??

Pankhuri Kumari 22nd Apr, 2020
Hii Dipanshu!
Please mention thr name of the examination for which you are enquiring. Now, the days required to complete the syllabus you mentioned, depends on you. Every person has a different ability and way to do things. If you are really dedicated and hardworking, you can complete the syllabus within 10-15 days, else, it may take as much time as you procrastinate. Firstly fix a timetable and follow it strictly knowing the topics you find tough and easy. Give more time to tough topics and solve question banks and previous year question papers to get an idea of the exam and the type of questions asked. This will help you cover up the syllabus well and soon.
Hope this helps.
Good luck !
2789 Views

In triangleABC and triangle XYZ, if angleA and angleX are acute angles such that cosA=cosX then show that angleA=angleX.

Awanya Dabas 11th Apr, 2020

Hey!

This is the solution:

We know that,

cosA= AB/ AC

cosX= XY/ XZ

Now, it is given that cosA= cosX

Therefore, AB/AC= XY/XZ

Let, these fractions be equal to k.

Therefore, AB= k.XY and AC= k.XZ ........(1)

Now, we need to find BC/ZY

So, BC/ZY= sqrt[AC^2- AB^2]/ sqrt[XZ^2- XY^2]

Putting the values from equation (1),

BC/ZY= k

Therefore, AB/XY= AC/XZ= BC/ZY

Therefore, the two triangles are similar.

And by property of similarity, angleA= angleX.

Hope this answer helps!

41 Views

guyz i m in 12th (2020-21) and i m weak in trigonometry... what i should do... as it is known that trigonometry is very important in 12th also.... give me some tips and how i can improve it... i dont know trigonometric equations... otherwise basics are good and tell me what formulas i should learn

Sai Sri Nandan Ch 9th Apr, 2020

Hello,

In my opinion, trigonometry is easy to learn if you focus and try to understand why and what you do when some situation arises.

Firstly, you need to write all the related formulas in one page. All formulas ranging including sin2x, sin3x, tan2x, etc. etc. Then try to memorize them.

Now solve the NCERT book. Remember, when you solve, try to find reason for everything.

For example, if you are writing cos2x as 1-2sin^2x and not like 2cos^2x-1, then find the reason. It is probably because the denominator of the fraction is in terms of sinx. This will let both the terms cancel and make the problem simpler.

All the formulas mentioned in Class 11 and 12 NCERT must be prepared.

Hope this helps.

Thanks.

1866 Views

if a=cos2 and b=sin 7 ,then a)a>0,b >0 b)ab<0 c)a>b d)a
ADITYA KUMAR Student Expert 25th Mar, 2020
Hi

The correct option is (c) ab <0 dear.

Explanation is provided below :-

cos2<0 as we know cos(pi/2)=0 and (pi/2)is somewhere around 1.57

so it lies in the second quadrant (where values lie for 1 to 4.71).

In second quadrant, cos value is negative .

sin7>0 as we know sin(pi/2)=1 and (pi)is somewhere around 6.28

so after one complete rotation it lies in the first quadrant (where values lie for 0 to 1.57) .

In first quadrant, sin value is positive.

so, ab<0  ,as a negative number multiplied by a positive number gives negative number .


Thankyou

5311 Views

trigonometry transformation formulas

Sai Sri Nandan Ch 24th Mar, 2020

Hello,

There are 8 Trigonometric Transformation Formulas. The beauty of these formulas is that addition of two trigonometric ratios can be converted into multiplication and vice versa. This will help to cancel terms from numerator and denominator or will let you split the numerator into two different fractions.

2 \sin A \cos B = \sin (A + B) + \sin (A - B) \\ \\ 2 \cos A \sin B = \sin (A + B) - \sin (A - B) \\ \\ 2 \cos A \cos B = \cos (A + B) + \cos (A - B) \\ \\ 2 \sin A \sin B = \cos (A - B) - \cos (A + B)

By replacing A+B as C and A-B as D, we can rewrite the formulas in another fashion:

\sin C + \sin D = 2 \sin \frac{1}{2}( C + D) \cos \frac{1}{2}( C - D) \\ \\ \sin C - \sin D = 2 \sin \frac{1}{2}( C - D) \cos \frac{1}{2}( C + D) \\ \\ \cos C + \cos D = 2 \cos \frac{1}{2}( C + D) \cos \frac{1}{2}( C - D) \\ \\ \cos D - \cos C = 2 \sin \frac{1}{2}( C + D) \sin \frac{1}{2}( C - D)

Hope this helps.

Thanks.

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