Question : What is the least possible value of p for which the number 84pp153p is divisible by 9?
Option 1: 2
Option 2: 1
Option 3: 7
Option 4: 5
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Answer (1)
24th Jan, 2024
Correct Answer: 2
Solution :
A number is divisible by 9 if the sum of its digits is divisible by 9.
Given number = 84pp153p
The sum of digits without including p = 8 + 4 + 1 + 5 + 3 = 21
⇒ The least possible value of p is 2, which will make the sum of the digits 27, which is divisible by 9.
Hence, the correct answer is 2.
Comments (0)
How to crack SSC CHSL
Candidates can download this e-book to give a boost to thier preparation.
Related Questions
Know More about
Upcoming Exams
Exam Date:
2 Mar, 2025
- 20 Mar, 2025
Exam Date:
13 Apr, 2025
- 13 Apr, 2025
Exam Date:
13 Apr, 2025
- 13 Apr, 2025
Preliminary Exam
Exam Date:
25 May, 2025
- 25 May, 2025
