Question : A certain number of men completed a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. The number of men originally was:
Option 1: 36
Option 2: 40
Option 3: 30
Option 4: 32

Question

Question : A piece of work can be completed by P and Q together in 24 days, and the same piece of work can be completed by R alone in 60 days. If P and R together can do the same work in 36 days, then find the time taken by Q to complete this piece of work alone.

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Answer 1

Correct Answer: 40

Solution : Given:
Let the original no of men be $x$ .
$x$ men can finish it in 60 days,
and $(x + 8)$ men can finish in 50 days.
$M_{1} D_{1} = M_{2} D_{2}$ , where $M_{1}$ and $M_{2}$ are men and $D_{1}$ and $D_{2}$ are days.
$\Rightarrow 60 x = 50 (x + 8)$
$\Rightarrow 10 x = 400$
$∴ x = 40$
So, there were 40 men originally.
Hence, the correct answer is 40.

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Question : A certain number of men completed a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. The number of men originally was:Option 1: 36Option 2: 40Option 3: 30Option 4: 32

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Question : A certain number of men completed a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. The number of men originally was:
Option 1: 36
Option 2: 40
Option 3: 30
Option 4: 32