1482 Views

1g sample of CaCO3 react with 10ml of 2M HCl solution.unused HCl require 100ml of 0.1M NaOH for complete neutralisation


Piyush keshri 17th May, 2018
Answer (1)
yash raj 19th May, 2018

hello piyush 

This is a case of limiting reagent, limiting reagents are those reagents which  control the amount of product formed by depleting earlier. 

from reaction of HCL and NaOH we found the HCL left was =0.01 moles

total HCL provided was=0.02 moles

so HCL consumed was =0.01 moles

so moles of CaCO3 used= 0.005 , which is half the no of moles of CaCO3 provided.

so % purity =50%


hope it helps

Related Questions

Amity University | B.Sc Admis...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
NIELIT University(Govt. of In...
Apply
Campuses in Ropar, Agartala, Aizawl, Ajmer, Aurangabad, Calicut, Imphal, Itanagar, Kohima, Gorakhpur, Patna & Srinagar
JSS University Mysore 2025
Apply
NAAC A+ Accredited| Ranked #24 in University Category by NIRF | Applications open for multiple UG & PG Programs
Geeta University | B.Sc Admis...
Apply
47 years of academic excellence | 40 LPA-Highest Package Offered
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books