Question : A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days. They started the work together and completed the work such that B was not working in the last 2 days and A did not work in the last 3 days. In how many days (total) was the work completed?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution :
Given: A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days.
Use the formula, Total work = efficiency × time.
| Time | Efficiency | Total work | |
| A | 14 |
|
56 |
| B | 28 |
|
56 |
| C | 56 |
|
56 |
For the last 2 days, B has not worked, while A has not worked for the last 3 days.
Let the entire work be finished in
⇒
⇒
⇒
⇒
⇒
Hence, the correct answer is
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