152 Views

a charge q is placed at the center of the line joining 2 equal charges Q. the system of the 3 charges will be in equilibrium of q is equal to (a) - Q/2 (b)- Q/4 (c) Q/4 (d) Q / 2


Rashi 13th Jun, 2020
Answer (1)
Mounika Sonti 13th Jun, 2020

Hello!!!!

Hope you are doing great!!!!

Given that a charge q is placed at the center C of line joining two equal charges Q each,at points A and B.

Let AB=2a

If the net force on each charge will be 0(zero) ,then the system will be in equilibrium.

let the charge Q is present at A.

At equilibrium state ,the total force on this charge is given by

1/4π e0*qQ/a^2 + 1/4π e0*qQ/2a^2 =0

=1/4π e0*qQ/a^2 = - 1/4π e0*qQ/2a^2

on solving we get,

q=-Q/4

Hope it helps!!!!

Thank you!!!!


1 Comment
Comments (1)
13th Jun, 2020
thnx mam😊
Reply

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books