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a charge q is placed at the center of the line joining 2 equal charges Q. the system of the 3 charges will be in equilibrium of q is equal to (a) - Q/2 (b)- Q/4 (c) Q/4 (d) Q / 2


Rashi 13th Jun, 2020
Answer (1)
Mounika Sonti 13th Jun, 2020

Hello!!!!

Hope you are doing great!!!!

Given that a charge q is placed at the center C of line joining two equal charges Q each,at points A and B.

Let AB=2a

If the net force on each charge will be 0(zero) ,then the system will be in equilibrium.

let the charge Q is present at A.

At equilibrium state ,the total force on this charge is given by

1/4π e0*qQ/a^2 + 1/4π e0*qQ/2a^2 =0

=1/4π e0*qQ/a^2 = - 1/4π e0*qQ/2a^2

on solving we get,

q=-Q/4

Hope it helps!!!!

Thank you!!!!


1 Comment
Comments (1)
13th Jun, 2020
thnx mam😊
Reply

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