Hi Aspirant!
As mentioned that length of minute hand is 10 cm, so average displacement will be 2*10=20 cm (from 6.00 AM to 6.30 AM as it moves, the starting point is 12 and ending point is 6). And the time taken is 30 minutes (given).
As we know, average velocity = average displacement/ time taken
therefore, average velocity = 20/30 = 2/3 cm/minute.
Hope it helps to clear your dilemma, thankyou!
Question : The minute hand of a clock is 20 cm long. Find the area on the face of the clock swept by the minute hand between 8 a.m. and 8:45 a.m.
Option 1: $\frac{6600}{7}$ cm2
Option 2: $\frac{6600}{9}$ cm2
Option 3: $\frac{6600}{18}$ cm2
Option 4: $\frac{6600}{14}$ cm2
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