7 Views

Question : A consumer's utility function is $U=X Y$. If the consumer is currently consuming $\mathrm{X}=5$ and $\mathrm{Y}=4$, what is the marginal rate of substitution (MRS) of $\mathrm{X}$ for $\mathrm{Y}$ ?

Option 1: 4/5

Option 2: 5/4

Option 3: 20/16

Option 4: 16/20


Team Careers360 3rd Jan, 2024
Answer (1)
Team Careers360 7th Jan, 2024

Correct Answer: 4/5


Solution : The correct answer is (a) $4 / 5$

To find the marginal rate of substitution (MRS) of $\mathrm{X}$ for $\mathrm{Y}$, we need to calculate the ratio of the marginal utility of $\mathrm{X}$ to the marginal utility of $\mathrm{Y}$.

The utility function is $\mathrm{U}=\mathrm{XY}$.
To find the marginal utility of $\mathrm{X}$, we differentiate the utility function with respect to $\mathrm{X}$ :
$
\partial \mathrm{U} / \partial \mathrm{X}=\mathrm{Y}
$

To find the marginal utility of $\mathrm{Y}$, we differentiate the utility function with respect to $\mathrm{Y}$ :
$
\partial \mathrm{U} / \partial \mathrm{Y}=\mathrm{X}
$

Now we can calculate the MRS:
$
\begin{gathered}
\mathrm{MRS}=(\partial \mathrm{U} / \partial \mathrm{X}) /(\partial \mathrm{U} / \partial \mathrm{Y}) \\
\quad=\mathrm{Y} / \mathrm{X}
\end{gathered}
$

Substituting $\mathrm{X}=5$ and $\mathrm{Y}=4$ :
$
\operatorname{MRS}=4 / 5
$

Therefore, the marginal rate of substitution (MRS) of $\mathrm{X}$ for $\mathrm{Y}$ is $4 / 5$.

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
East Point College | MBA Admi...
Apply
NBA Accredited | AICTE Approved
Chitkara University MBA Admis...
Apply
NAAC A+ Accredited | 100% CAMPUS RECRUITMENT
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books