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A force of 100N applied on a block of mass 3kg as shown in fig. The coefficient of friction between the surface and block is 1/4. The friction force acting on the block is


prachiverma2502 23rd May, 2020
Answer (1)
Mounika Sonti 25th May, 2020

Hello!!!

Hope you are doing great!!!

Given,

Force F=100N

mass=3kg

Coefficient of friction=μ  = 1/4

As we know,F=ma

a=F/m

a=100/3 m/s^2

acceleration=100/3 m/s^2

frictional force f=μ ma

therefore f=1/4*3*100/3

f=25N

Frictional force f=25N

Hope it helps!!!!!!

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