Question : A girl, walking at $\frac{5}{6}$ of her usual speed, misses the bus by 7 minutes. How long does it usually take to reach the bus stop?
Option 1: 24 minutes
Option 2: 35 minutes
Option 3: 30 minutes
Option 4: 60 minutes
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Correct Answer: 35 minutes
Solution : Given, A girl, walking at $\frac56$ of her usual speed, misses the bus by 7 minutes. We know, Distance covered = speed × time taken Let the usual speed and usual time to reach the bus be $v$ and $t$, respectively. ⇒ The distance of the bus from her home is $vt=\frac{5v}{6}(t+7)$ ⇒ $6t = 5t + 35$ ⇒ $t$ = 35 minutes Hence, the correct answer is 35 minutes.
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Question : If a man travels at 12.5 percent less speed than his usual speed, then he will reach 9 minutes late. What is the usual time taken by him?
Option 1: 63 minutes
Option 2: 70 minutes
Option 3: 56 minutes
Option 4: 49 minutes
Question : If Mohan travels at 60% speed of his usual speed, then he will arrive 10 minutes late. What is the usual time taken by him?
Option 1: 12.5 minutes
Option 2: 15 minutes
Option 3: 10 minutes
Option 4: 20 minutes
Question : It takes 6 hours to clean a garden. In 2 hours 30 minutes, what part of the garden will be cleaned?
Option 1: $\frac{5}{2}$
Option 2: $\frac{5}{12}$
Option 3: $\frac{5}{8}$
Option 4: $\frac{5}{6}$
Question : A person covers the first 30 km in 60 minutes and the next 40 km in 30 minutes. What is his average speed for the whole journey?
Option 1: $\frac{140}{3}$ km/hr
Option 2: 30 km/hr
Option 3: $\frac{160}{3}$ km/hr
Option 4: 60 km/hr
Question : What is the value of $\left[\frac{1}{5}+\left\{\frac{1}{6}\right.\right.$ of $\left.\left.\left(\frac{42}{35} \div \frac{6}{25}\right)–\left(\frac{2}{7} \times \frac{6}{5} \div \frac{18}{42}\right)\right\}+\frac{19}{30}\right]$?
Option 1: $\frac{17}{15}$
Option 2: $\frac{13}{15}$
Option 3: $\frac{14}{15}$
Option 4: $\frac{11}{15}$
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