Question : A hemispherical bowl has an internal radius of 6 cm. The internal surface area would be: (Take $\pi =3.14$)
Option 1: 225 cm2
Option 2: 400 cm2
Option 3: 289.75 cm2
Option 4: 226.08 cm2
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Correct Answer: 226.08 cm 2
Solution :
Given: Internal radius, $r$ = 6 cm.
Internal surface area of hemispherical bowl = $2\pi r^2$
= 2 × 3.14 × 6 × 6 = 226.08 cm
2
Hence, the correct answer is 226.08 cm
2
.
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