Question : A man is born in the year 1896 A.D. If in the year $x^2$ A.D. His age is $(x-4)$, the value of $x$ is:
Option 1: 40
Option 2: 44
Option 3: 36
Option 4: 42
Correct Answer: 44
Solution : Let the man's age be $x$. According to the question, $x^2 - 1896 = x - 4$ or, $x^2 - 1896 - x + 4 = 0$ or, $x^2 - x - 1892 = 0$ or, $x^2 - 44x + 43x - 1892 = 0$ or, $x$ = 44, – 43 Since age can not be negative, so, $x = 44$ Hence, the correct answer is 44.
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Question : If $x^2-8x+1=0$, what is the value of $(x^2+\frac{1}{x^2})$?
Option 1: $18$
Option 2: $34$
Option 3: $40$
Option 4: $62$
Question : Directions: A man was 32 years of age when he had his first son. His wife was 35 years of age when his son attained the age of 7 years. The difference in age between the man and his wife is?
Option 1: 7 years
Option 2: 3 years
Option 3: 5 years
Option 4: 4 years
Question : Directions: A man was 31 years of age when his son was born. His wife was 26 years of age when his son attained the age of 7 years. What is the difference between the man's age and his wife's age?
Option 2: 9 years
Option 4: 12 years
Question : If $x^2-7x+1=0$, what is the value of $(x+\frac{1}{x})$.
Option 1: 7
Option 2: 3
Option 3: 51
Option 4: 47
Question : What is the value of $\frac{x^2-x-6}{x^2+x-12}÷\frac{x^2+5x+6}{x^2+7x+12}$?
Option 1: $1$
Option 2: $\frac{(x-3)}{(x+3)}$
Option 3: $\frac{(x+4)}{(x-3)}$
Option 4: $\frac{(x-3)}{(x+4)}$
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