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Question : A man is twice as fast as a woman and twice as fast as a boy at doing work. If all of them a man, a woman, and a boy can finish the work in 7 days, in how many days will a boy do it alone?

Option 1: 49

Option 2: 7

Option 3: 6

Option 4: 42


Team Careers360 9th Jan, 2024
Answer (1)
Team Careers360 18th Jan, 2024

Correct Answer: 49


Solution : Given: A man is twice as fast as a woman and twice as fast as a boy at doing work.
According to the question,
1 man = 2 women = 4 boys
The efficiency of man : woman : boy = 4 : 2 : 1
Taking for a boy,
$\therefore$ 1 man + 1 woman + 1 boy are equivalent to (4 + 2 + 1 = 7 boys).
We know, that M1D1 = M2D2, where M1 and Mare the number of boys and Dand Dare their respective times to finish the work.
⇒ 7 × 7 = 1 × D2
$\therefore$ D2 = 49 days
Hence, the correct answer is 49.

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