Question : A man makes four trips of equal distances. His speed on the first trip was 720 km/hr and in each subsequent trip, his speed was half of the previous trip. What is the average speed of the man in these four trips?
Option 1: 104 km/hr
Option 2: 156 km/hr
Option 3: 192 km/hr
Option 4: 288 km/hr
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Correct Answer: 192 km/hr
Solution :
A man makes four trips of equal distances.
His speed on the first trip was 720 km/hr.
In each subsequent trip, his speed was half of the previous trip.
Let's denote the distance of each trip as d.
For the first trip, his speed was 720 km/hr, so the time taken was =
For the second trip, his speed was
So the time taken was =
For the third trip, his speed was
So the time taken was =
For the fourth trip, his speed was
So the time taken was =
So, the total distance travelled was 4d, and the total time taken was =
Average speed =
=
=
=
=
= 192 km/hr
Hence, the correct answer is 192 km/hr.
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