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I(m) at FSD is 0.1 mA, so I(m) at 0.5 FSD is 0.05 mA I(s) at FSD is 9.9 mA, so I(s) at 0.5 FSD is 4.95 mA Total I=I(m)+I(s) = 5 mA In analog systems, full scale maybe defined by the maximum voltage available or the maximum deflection/FSD or indication of moving coil meter or galvanometer.
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