a police party is chasing a dacoit in a jeep moving with constant speed v. the dacoit is on a motor cysle. when he is at distance x from the jeep, he accelerates from rest at a constant rate alpha. is the relation v^2=2alpha.x is correct? how?
Hello candidate,
Using the third equation of motion, that the square of final velocity is equal to the arithmetic sum of the square of initial velocity and 2 multiplied by the acceleration into the distance.
So, taking the initial velocity is equal to zero the expression becomes v^2= u^2+ 2*alpha*distance. So, the expression is perfectly correct.
Hope That this information helps you!!
Have a good day.