Question : A seller uses a faulty weight in place of a 2 kg weight and earns a 25% profit. He claims that he is selling at the cost price in front of the customers but uses a faulty weight. How much error is there in the 2 kg weight to gain 25%?
Option 1: 250 gm
Option 2: 400 gm
Option 3: 500 gm
Option 4: 300 gm

Question

Question : A seller uses a faulty weight in place of a 2 kg weight and earns a 25% profit. He claims that he is selling at the cost price in front of the customers but uses a faulty weight. How much error is there in the 2 kg weight to gain 25%?

Option 1: 250 gm

Option 2: 400 gm

Option 3: 500 gm

Option 4: 300 gm

Team Careers360 · Accepted Answer

Correct Answer: 400 gm

Solution : Let the error be m gm.
Percentage profit = $[\frac{ ext{Error}}{ ext{(True weight–Error)}}] × 100 $
According to the question,
$25 = (\frac{m}{(2000 - m)}) × 100$
$⇒ \frac{25}{100} = \frac{m}{(2000 - m)}$
$⇒ \frac{1}{4} = \frac{m}{(2000 - m)}$
$⇒ 2000 - m = 4m$
$⇒ 5m = 2000$
$⇒ m = \frac{2000}{5} = 400$ gm
∴ The faulty weight used by the seller has the error of 400 gm.
Hence, the correct answer is 400 gm.

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