781 Views

A sphere of diameter r is cut from a sphere of radius r such that the centre of mass the remaining mass be at maximum distance from orinal center. the distance is


ABHILIPSHA BARAL 6th Jun, 2020
Answer (1)
Mounika Sonti 6th Jun, 2020

Hello!!!

Hope you are doing great!!!

The radius of the bigger sphere=r

let x be the distance between center of mass from the original center of the sphere after the smaller sphere has cut.

let the density of the bigger sphere be d

mass of the bigger sphere = 4/3* π r^3d

mass of the smaller sphere= 4/3* π(r/2)^3d

mass of the remaining sphere= 4/3* π r^3d - 4/3* π(r/2)^3d

on solving,we get,,,, 7/6* π r^3d

position of the center of mass of the complete sphere=0

=-x*7/6 π r^3d+r/2*4/3 π (r/2)^3d=0

on solving we get,x=r/14


Hope it helps!!!

Related Questions

UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES Integrated LLB Admission...
Apply
Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 LPA Highest CTC
Presidency University MBA Adm...
Apply
NAAC A+ Accredited | Highest CTC 10 LPA | Top Recruiters : Amazon, Accenture, KPMG, EY, Capgemini & many more
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES | BBA Admissions 2026
Apply
#36 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books