48 Views

a spring of force constant k is cut into lenghts of ratio 1:2:3 then we get three springs of length l/6, 2l/6, 3l/6 how did we get this?


shreerakshag39 22nd Aug, 2020
Answer (1)
Prabhav Sharma 22nd Aug, 2020

Hello,

Assume the length of the spring to be 'l'

Now the ratios of lengths in which the spring is cut is 1:2:3

That means the length of the three new springs will be x, 2x and 3x where x is equal to some constant.

Therefore, 1x + 2x + 3x = l

= 6x = l

= x = l/6

Now length of new springs will be l/6, 2l/6 and 3l/6

(Substituting the value of x = l/6)

Hope it is clear now.

3 Comments
Comments (3)
22nd Aug, 2020
thanks alot ...
it really helped me😇
Reply
22nd Aug, 2020
shreerakshag39 You are welcome. All the best :)
Reply
22nd Aug, 2020
Prabhav Sharma thank you....
how do u clear all ur physics concepts?
Reply

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
Maya Devi University LLM admi...
Apply
43.6 LPA Highest Package | 5.48 LPA Average Package | 150+ Courses in UG, PG, Ph.D
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Shri Khushal Das University L...
Apply
Approved by UGC | Robust Placement Assistance
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books