Question : A square of side 3 cm is cut off from each corner of a rectangular sheet of length 24 cm and breadth 18 cm, and the remaining sheet is folded to form an open rectangular box. The surface area of the box is:
Option 1: 468 cm2
Option 2: 396 cm2
Option 3: 612 cm2
Option 4: 423 cm2
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Correct Answer: 396 cm2
Solution : Length of rectangular sheet = 24 cm Breadth of rectangular sheet = 18 cm Side of cut-out square = 3 cm Length of the box $(l)$ = [24 – (3 + 3)] = 18 cm Breadth of the box $(b)$ = [18 – (3 + 3)] = 12 cm Height of the box $(h)$ = 3 cm Surface area of an open rectangular box = $lb + 2(bh + hl)$ = [18 × 12 + 2(12 × 3 + 3 × 18)] = [216 + 2(36 + 54)] = 216 + 180 = 396 cm2 Hence, the correct answer is 396 cm2.
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Question : The sum of the length and breadth of a cuboid is 4 cm. Length is three times the breadth. If the height of the cuboid is half of the sum of its length and breadth. Then what is the total surface area of the cuboid?
Option 1: 64 cm2
Option 2: 22 cm2
Option 3: 32 cm2
Option 4: 30 cm2
Question : The length, breadth, and height of a cuboid are in the ratio 3 : 4 : 6 and its volume is 576 cm3. The whole surface of the cuboid is:
Option 1: 216 cm2
Option 2: 324 cm2
Option 3: 432 cm2
Option 4: 460 cm2
Question : If the sum of the dimensions of a rectangular parallelepiped is 24 cm and the length of the diagonal is 15 cm, then the total surface area is:
Option 1: 420 cm2
Option 2: 275 cm2
Option 3: 351 cm2
Option 4: 378 cm2
Question : The length of a cuboid is thrice of its breadth and the height of a cuboid is twice its breadth. If the breadth of the cuboid is 6 cm, then what is the total surface area of the cuboid?
Option 1: 844 cm2
Option 2: 708 cm2
Option 3: 762 cm2
Option 4: 792 cm2
Question : The length, width, and height of a cuboidal box are 18 cm,12 cm, and 10 cm, respectively. What is the total surface area of the box?
Option 1: 1000 cm2
Option 2: 1048 cm2
Option 3: 1032 cm2
Option 4: 1120 cm2
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