93 Views

A total energy of the body excuting s.h.m isE then the kinetic energy when displacement is half of the amplitude is


Kanhaiya kumar 14th Aug, 2019
Answer (1)
siddhiarora2311_9776369 Student Expert 15th Aug, 2019

Hey Kanhaiya!

Displacement= a/2

Total energy=1/2 m* (omega)^2* (a)^2 ....(1)

KE when displacement= x is

1/2 m* (omega)^2* [(a)^2-(x)^2]

1/2 m* (omega)^2* [(a)^2-(a/2)^2]

3/4(1/2*m* (omega)^2* (a)^2) .....(2)

By dividing 2 by 1, we get: 3/4

Therefore total fraction is 3/4

Sorry to inform you but it's a career counseling website, try searching your answers on an educational forums next time.

Best of luck!

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Indrashil University | B.Tech...
Apply
Apply for B.Tech | AICTE Aproved | UGC Recognized | International Collaborations for Global Edge | 100% Placement Assistance
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings)
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024)
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books