hello aspirant,

according to your percentile you have less chances to get good or top NIT s althrough you are  obc category their is no chance 

so you have another chance to write jee mains in apirl,so prepare well don't miss the chance hope you may get and use carrer 360 for more updations to know information

check below link:https://r.search.yahoo.com/_ylt=AwrWpyZJinZcxAgALgznHgx.;_ylu=X3oDMTByb2lvbXVuBGNvbG8DZ3ExBHBvcwMxBHZ0aWQDBHNlYwNzcg--/RV=2/RE=1551301321/RO=10/RU=https%3a%2f%2fengineering.careers360.com%2ftags%2flist-of-nit-in-india/RK=2/RS=7BoBeUtd_aDAl_vj3dglEv5Gf.k-

hope this may help for you.

thank you.

Hello Aspirant,

 JEE Main is conducted twice an year(from 2019) by the National testing Agency(NTA) to provide admission into various undergraduate courses in Institutions like NITs,IIITs,CFTIs etc..One session of JEE main is already over in January and NTA also started receiving applications for those who want to appear for JEE main second session which is conducted in April.

        By the percentile you scored, you will definitely be qualified to appear for JEE Advanced which is conducted for admissions into undergraduate courses in various IITs. And also since, percentile is introduced this year , it is unable to predict exactly whether you have a chance in NITs or not. But based on the percentile, you can calculate your All India Rank(AIR) using the below given formula:

 As per the statistics given by the NTA, 8,74,679 candidates appeared for the exam across four days with two sessions each i.e for a total of eight sessions.There are a total of 15 students who scored 100 percentile in these sessions.

 To calculate you JEE main score, you need  to know the percentage of people ahead of you.For that, you have subtract your percentile from 100 and it is multiplied with 8,74,679 divided by 100.

Therefore, the formula to calculate the JEE Main 2019 for January Session:

JEE Main rank(probable)=(100-NTA percentile)*874679/100

So, your All India rank will be probably around 35000. 

https://engineering.careers360.com/articles/jee-main-cutoff

Hope you got the information you require!

All the best!!

Hello...
According to your percentile your general rank would be around 35000 and category rank would be around 9000.You can get some nits.All the Northeast Nits are easily accessible to you to take admission in good branch also.If you mention your state ,I will give you info more effectively.You can get Metallurgical engineering, production engineering Mining engineering in jamshedpur.You can get electronic in nit Manipur.
Hope it helps you.
For more information mention your state.
Good luck.

Hello aspirant,
Your expected rank is calculated based on your NTA percentile by using the formula:
Rank =(100-NTA percentile)*874469/100
Your expected rank may be 34,978(approximately).
It is difficult to get in nits and you have another chance to improve your percentile so concentrate on that.

But you have second JEE mains exam which will be conducted in the month of April and the official cut offs will be released after that exam.
So please wait for the official cut offs and prepare well for the exam.
For the previous year cut offs please go through the link once.
https://www.google.co.in/amp/s/engineering.careers360.com/articles/jee-main-cutoff/amp
If you have any queries please drop a comment.
Thank you!!!!

Hello..
The formula to calculate approximate rank is :
(100- percentile)*874469/100.

If if we implement your percentile in the formula your approximate general rank will be around 34,978.

For this rank you will get a seat in good nit. To get a seat in even more good nit I request you to improve your percentile in the April exam so that you can get seat in even more good nit.

For more details please visit the link:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff/amp

All the best..

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