Question : Directions: Select the option related to the third letter cluster in the same way as the second letter cluster is related to the first letter cluster.
LEMON : MDOMQ :: AXILE : ?
Option 1: BWKJH
Option 2: BVKJH
Option 3: BWLJH
Option 4: BVJKH
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Correct Answer: BWKJH
Solution :
Given:
LEMON : MDOMQ :: AXILE : ?
Add and subtract the natural number in the alternative letter of LEMON, to obtain the required code –
L + 1 = M, E – 1 = D, M + 2 = O, O – 2 = M, N + 3 = Q
Thus, LEMON is coded as MDOMQ.
Similarly, by following the same pattern for AXILE : ? →
A + 1 = B, X – 1 = W, I + 2 = K, L – 2 = J, E + 3 = H
Thus, AXILE is coded as BWKJH. Hence, the first option is correct.
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