Question : Find the value of $[49^{\frac{3}{2}}+49^{-\frac{3}{2}}]$.
Option 1: $\frac{11749}{343}$
Option 2: $\frac{117550}{343}$
Option 3: $\frac{117659}{343}$
Option 4: $\frac{117650}{343}$
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Correct Answer: $\frac{117650}{343}$
Solution : Given: $[49^{\frac{3}{2}}+49^{-\frac{3}{2}}]$ Simplifying this expression by factorising, we have, = $[(7^{2})^{\frac{3}{2}}+(7^{2})^{\frac{–3}{2}}]$ = $[7^{3}+7^{–3}]$ = $[343+\frac{1}{7^{3}}]$ = $[343+\frac{1}{343}]$ = $[\frac{117649+1}{343}]$ = $\frac{117650}{343}$ Hence, the correct answer is $\frac{117650}{343}$.
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Question : Find the value of the given expression: $\frac{(4\frac{1}{3}+3\frac{1}{3}\times 1\frac{4}{5}\div 3\frac{3}{4}\times (1\frac{1}{2}+1\frac{1}{3}))}{(\frac{2}{3}\div \frac{5}{6}\times \frac{2}{3})}$
Option 1: $11 \frac{3}{8}$
Option 2: $10\frac{1}{8}$
Option 3: $14\frac{3}{8}$
Option 4: $16\frac{5}{8}$
Question : If $\operatorname{cosec} \theta=1 \frac{7}{22}$, then find the value of $\cot ^2 \theta$.
Option 1: $\frac{49}{484}$
Option 2: $\frac{357}{484}$
Option 3: $\frac{225}{484}$
Option 4: $\frac{7}{22}$
Question : If $\sec \theta=2 \frac{4}{23}$,find the value of $\tan^2 \theta$.
Option 1: $2 \frac{16}{529}$
Option 2: $1 \frac{200}{529}$
Option 3: $3 \frac{384}{529}$
Option 4: $3 \frac{177}{529}$
Question : The value of $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$ is:
Option 1: $\frac{1}{2}$
Option 2: $2\frac{1}{2}$
Option 3: $3\frac{1}{2}$
Option 4: $9\frac{1}{2}$
Question : If $\left(3 y+\frac{3}{y}\right)=8$, then find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Option 1: $5\frac{1}{9}$
Option 2: $4\frac{5}{6}$
Option 3: $7\frac{1}{9}$
Option 4: $9\frac{1}{9}$
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