hiii,Here is the solution to the questionDistance between object and image = 10 cmMagnification = height of image / height of object = v/uM= 1/4 (given)m= v/u =1/4 u = 4vu-v = 10cmso, 4v-v = 10 cm v= 10/3 cm hence u =40/3 cmnow applying the lens formula1/f = 1/v -1/u = -3/10 + 3/40 = - 4.4 cmtherefore the focal length is -4.4cmI hope you understand the solution.Feel free to revert back for any queries. Thank you!!!
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