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Galileo writes that for angles of projection of a projectile at angles (45+alpha) and (45-alpha) the horizontal ranges describe by the pro


KARSANG YANI 9th Jul, 2019
Answer (1)
NAVEEN MEENA Student Expert 9th Jul, 2019

Dear Karsang,

For complementary angles, range will be same. Therefore,

For angle (45°-θ), R = u2sin(90° - 2θ)/g = u2 cos 2θ/g

For angle 45°+θ), R = u2sin(90° + 2θ)/g = u2 cos 2θ/g

So, the ratio of the projectile is - 1:1

Thus answer is 1:1

All the best

Feel free to ask for any query

1 Comment
Comments (1)
9th Jul, 2019
Thnk you so much
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