25 Views

How kmno4 is a powerful oxidation an agent in redox titration write an examples


Kalyan Annapureddy 12th Dec, 2021
Answer (1)
Prateek kumar 12th Dec, 2021

Dear student,

You can calculate the oxidation states of the central atoms by the fact that a molecule is neutral so the sum of the oxidation states of all atoms is equal to zero. If they are in their highest state then they are suitable oxidizing agents.

  • KMnO4

KMnO4 has K in +1, O in -2 state, so, Mn will have 1 + Mn + 4 (-2) = 0
Mn + 1 – 8 = 0
Mn = +7, which is its maximum oxidation state.
-Iodine is in 0 oxidation state, as it is a monatomic molecule, so the oxidation states will cancel out and become 0. But it is electronegative and can gain electrons so it is an oxidizing agent.

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books