Hello,

Every year the cut off changes which depends on total number of candidates appeared, difficulty level of the paper, total number of seats available, previous year cut off etc. When the cut off is subjected to change it is quite difficult to indicate the exact score. But a safe score is minimum 180-210 marks to get seat in a decent NIT in Computer Science and Engineering  under OBC category considering the previous year cut off trends.

If you want to prepare for JEE Main upcoming sessions you can register for our JEE Main knockout and prepare

https://learn.careers360.com/knockout-jee-main-april/?icn=jee-main-knockout_landing-page&ici=nav-header_engg

To know the colleges in which you may get seat you can use our JEE Main college predictor

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Please Check the cut off for NITs and IIITs so that you will get some idea about the cut off trends

https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits