i got 90.23 percentile in jee exam (9 jan-shift 2 from general catagiry).....nd im from haryana....can i get NIT???
Answer (1)
25th Jan, 2020
To calculate the JEE main rank,you can use this formula ((100-your total percentile)*869010/100).This formula will give your general category rank(Common list rank).And your rank is approximately 84,902.It will be difficult to predict your OBC rank because we dont have the exact data of number of OBC candidates who have appeared for the exam.
Since you can avail home state of Haryana,admissions into NIT Kurukshetra will be more easier.You can see the previous year's cutoff of NIT kurukshetra in the below given website:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra/amp
To know about all the possibilities of your admission into various colleges,visit the below given website.You will have to enter the details asked such as your percentile,category,home state etc..and the possibilities will be predicted.
https://engineering.careers360.com/jee-main-college-predictor
Since you can avail home state of Haryana,admissions into NIT Kurukshetra will be more easier.You can see the previous year's cutoff of NIT kurukshetra in the below given website:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra/amp
To know about all the possibilities of your admission into various colleges,visit the below given website.You will have to enter the details asked such as your percentile,category,home state etc..and the possibilities will be predicted.
https://engineering.careers360.com/jee-main-college-predictor
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