I got 94.4918712 in JEE mains 2019 can I get nit or not?? Should I apply for April exam??
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Answers (2)
21st Feb, 2019
Hi Candidate,
your general rank will be around 56K. NTA have not officially announced any cut off lists yet but last year the closing rank for NITs was around 39K. You have low chances to get a seat at NITs but you might get one at IIITs or GFITs. you can check previous year's cut off trends here : https://engineering.careers360.com/articles/jee-main-cutoff/amp
All the best :)
your general rank will be around 56K. NTA have not officially announced any cut off lists yet but last year the closing rank for NITs was around 39K. You have low chances to get a seat at NITs but you might get one at IIITs or GFITs. you can check previous year's cut off trends here : https://engineering.careers360.com/articles/jee-main-cutoff/amp
All the best :)
Comments (0)
21st Feb, 2019
Hello Aspirant
.
Firstly congrats for your percentile score!
But it is difficult to get nit Colleges with this percentile score you have to improve your percentile score by giving attempt to April jEE mains exam.
.
Use this formula to predict the rank:
You have to wait for the official results.if you want to compare with previous years cutoff of nits/ IIIt you can go through the below link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits/amp
.
If you have any questions further let me know
.
Thank you!!!
.
Firstly congrats for your percentile score!
But it is difficult to get nit Colleges with this percentile score you have to improve your percentile score by giving attempt to April jEE mains exam.
.
Use this formula to predict the rank:
- Rank Formula = (100 - your total score) X 874469 /100.
- Your expected rank is 48183 by using above formula.
- You should should get around 15000 rank to get seat in nits.
You have to wait for the official results.if you want to compare with previous years cutoff of nits/ IIIt you can go through the below link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits/amp
.
If you have any questions further let me know
.
Thank you!!!
Comments (0)
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