It depends upon the JEE Main and JEE Advance cut offs, If You manage to qualify the exam by achieving the cut off, You can apply for JOSAA Counselling. It should be noted the cut off for EWS/SC/ST/FEMALES/OBC category is lower than the general category

If you manage to qualify JEE Main Cutoff, You would be eligible for JEE Advance which is the intake exam for IITs as mentioned above.


However It is usually advised to fill the choices as per the preference of colleges and departments, for example CSE in NIT Trichy is your priority followed by CSE in NIT Warangal, you can fill CSE at NIT Trichy at serial number 1 and CSE at NIT Warangal at serial number 2 and so on and so forth. However to get any NIT, you must have qualified JEE Mains and to get any IIT, you must have qualifies JEE Advanced

But the previous cut offs of colleges should be taken in consideration, it is better to research over the cut off of colleges then make a preference list of colleges and fill accordingly

For the college preferences and the courses provided by these colleges and to know which colleges participate in the JOSAA counselling, please go to the below mentioned link: https://engineering.careers360.com/articles/josaa-participating-institutes/amp

For college prediction as per your marks and rank, please go through the below mentioned link: https://dqxeclau.top/college-predictor

Rest for information on any particular college, you can dig their official site for better information

HELLO ASHUTOH 

FIRST OF ALL CONGRATULATION ON SCORING SO WELL IN THE EXAM , YOU CLEARLY HAVE GOOD CHANCES OF GETTING INTO SOME GREAT NITS.

BUT AS PER NOW WE DONT HAVE ANY CLEAR DECLARATION OF RESULTS, SO YOU HAVE TO WAIT FOR THE OFFICIAL ANNOUCHMENT IN APRIL.

FOR THE TIMING IF YOU WANT YO CAN GO AHEAD AND CHECK THE PREVIOUS YEARS CUT OFF FOR THE SAME.

HAPPY LEARNING!!

Hi there.

The final cut off list will be declared by NTA after the April session of the JEE mains examination.

As for now, your probable rank can be calculated. 

Now, A total of 874469 candidates wrote the exam. Since the percentile is calculated from a scale ranging from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 874469 /100 multiplied by the percentage of people who are ahead of you to arrive at the rank.

Therefore, the formula to calculate the JEE Main 2019 rank for January 2019 is

JEE Main 2019 rank (probable) = (100-96.02) X 874469 /100 = 34804(approximately)


This rank may inflate or deflate depending on the total number of candidates who write the examination. in the April session. 

You could take a probable calculation and see where you stand. This means that you take a hypothetical number of the candidates who will appear in April. If you go by past trends, the figures are somewhat between 11 lakhs to 12 lakhs. Using this as a basis, use the NTA score and see which JEE Main rank you will get. 

Using the same formula,

If NTA percentile score is 96.02, JEE Main rank will be (100-96.02) X 1200000/100 = 47760

Now, using this estimated calculation, you can check previous year cut off trends and think of an idea of the probable colleges.

Check the following links for previous year trends in cut off :

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff/amp

For college predictor of JEE mains, check the link below:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-college-predictor/amp

Hope this helps.
Good luck!

NIT Warangal

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