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i have got 89.24 percentile in jee main if lam eligible for jee advance and did iget in any nit


Aswin 29th Jan, 2020
Answers (3)
ARNAV SATRUSAL 29th Jan, 2020

Hi Aswin,

As the official cutoff will be declared after April JEE Mains exam, I will advice you not to think about cutoff and waste your precious time rather, I will advice you to give you best effort for the April attempt and try scoring around 170-180 marks which will land you in a decent NIT and a branch of your choice .

As the number of students who will be appearing the April attempt is not known, So, it becomes very difficult to predict the cutoff percentile.

You can go through the link to check for different colleges:

Wishing you all the very best for your April attempt.

Muskan 29th Jan, 2020

Hi Aswin

It is difficult to predict score eligibility for JEE advance.

But you can predict your expected rank from the following formula :

(100 - 89.24 ) X 869010 / 100 so using this formula your expected rank will be

93 , 505 . But for april session if the number of students increase therefore instead of 869010 it would be number of candidates that appeared in April session. so it can only be predicted after April session.

For NIT , most probably you need 95 + percentile.

For more information you can refer to the link below :

All the best !!

Hope it helps :)



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Atulya Himanshu 29th Jan, 2020
Hi, Aswin

Its difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula


To Calculate the rank for B. Tech:
So rank formula is (100 - your total score) X 869010 /100



At this Score or Rank your Chances to qualify for jee advanced are high.


I hope you will increase your nta score in April and take admissions in nit or iiit.


You can predict your college through this link

https://engineering.careers360.com/jee-main-college-predictor


Hope this helps! All The Best!!


Feel free to ask if you have any more queries

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