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Hi dear,
You have scored 96.2 percentile in JEE main paper 2 that means your rank should be around 4485. You can also calculate your rank as
Rank=(100-your percentile)×869010÷100
Last year cutoff of NIT Trichy was
General-home state(opening and closing rank)and other state(opening and closing 4)
1189
2468
121
1075
OBC-NCL
793
1043
338
652
SC
175
271
131
163
ST
366
741
103
EWS
798
141
158
So if you belong from category then you have some chance otherwise you have to reappear in april month exam and perform better.
Hope it helps
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