I have scored 92.47 Nta in Jee mains2020. am i ellgible for Jee advance 2020?
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You are qualified for JEE ADVANCED
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Student Expert
21st Jan, 2020
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 65436 . Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.
At this point in time, it is difficult to predict the percentiles for JEE Advanced but going by previous years it will be 85 percentile and above. Going by that you have decent chances should you plan on appearing for JEE Advanced.
You haven't mentioned your Category but
Now to predict colleges, please use our college predictor:https://engineering.careers360.com/jee-main-college-predictor
At this point in time, it is difficult to predict the percentiles for JEE Advanced but going by previous years it will be 85 percentile and above. Going by that you have decent chances should you plan on appearing for JEE Advanced.
You haven't mentioned your Category but
Now to predict colleges, please use our college predictor:https://engineering.careers360.com/jee-main-college-predictor
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