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I scored 72.3% in physics chemistry and bio cbse boards (2020-21) and 37.85 percentile in gujcet... what will be my merit marks and rank? and what will be my percentile of boards marks?


riyadixit203 25th Aug, 2021
Answer (1)
Sai Kiran K 26th Aug, 2021

Hi Aspirant,

GUJCET (Gujarat Common Entrance Test) is the state level examination for Engineering and Pharmacy Programs conducted by GuJarat Secondary and Higher Secondary Education Board.  The Eligibility criteria of GUJCET is passed in 10+2 with 45% aggregate marks in Mathematics, Physics as compulsory subject and Chemistry, Biology, Computer as option subjects.

The GUJCET pattern for admission process for Bachelor of Engineering programs has 40% marks of examination weightage along with 60% Weightage marks of 12th Standard. So the Rank is decided based on this 40 -60 calculation.

let us consider you GUJCET percentage is A which is 72.3 and 12th Percentage is B which is 37.85

(0.4*A) + (0.6*B) - (0.4*72.3) + (0.6*37.85) = 51.63. So You overall Percentile would be 51.63% out of 100. Your rank would be around 35,000 - 40,000 According to 2019 cutoff. Hope you find this calculation helpful. All the best for you career.


Thanks & Good Luck!...

1 Comment
Comments (1)
26th Aug, 2021
Thanku so much sir.....for your respond but still there's a doubt....
This time in year 2021 the weightage for gujcet and boards is 50-50%
And I wanna know my percentile of cbse boards....my 12th percentage is 72.3%
Thanku sir 🤗
Reply

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