Question : If 7A425B is divisible by 36, then what is the value of A – B?
Option 1: 0
Option 2: 5
Option 3: 1
Option 4: 2
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 5
Solution : Given Number =7A425B For the number to be divisible by 36 it should be divisible by 4 and 9. For the number to be divisible by 4, the last two digits "5B" should be divisible by 4. Then the possible values of B are 2 and 6. Now, for the number to be divisible by 9, Sum of digits = 7 + A + 4 + 2 + 5 + B = 18 + A + B should be divisible by 9. If B = 2, then the value of A = 7 [Since 18 + 7 + 2 = 27 is divisible by 9] If B = 6, then the value of A = 3 [Since 18 + 3 + 6 = 27 is divisible by 9] So, the possible values of A – B are (7 – 2) i.e. 5 or (3 – 6) i.e. – 3. After checking the given options, we get A – B = 5 Hence, the correct answer is 5.
Candidates can download this e-book to give a boost to thier preparation.
Application | Eligibility | Admit Card | Answer Key | Preparation Tips | Result | Cutoff
Question : If $x^{3}+2x^{2}-5x+k$ is divisible by $x+1$, then what is the value of $k$?
Option 1: –6
Option 2: –1
Option 3: 0
Option 4: 6
Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Option 1: 2
Option 4: 0
Question : If the 4-digit number 48ab is divisible by 2, 5, and 7, then what is the value of (10a – b)?
Option 2: 20
Option 3: 10
Option 4: 30
Question : 6m61 is divisible by 11. What is the value of m?
Option 2: 4
Option 3: 3
Option 4: 5
Question : If $ a^{2}+a+1=0$, then the value of $a^{5}+a^{4}+1$ is:
Option 1: $a^2$
Option 2: $1$
Option 3: $0$
Option 4: $a+1$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile