Question : If $x^{3}+2x^{2}-5x+k$ is divisible by $x+1$, then what is the value of $k$?
Option 1: –6
Option 2: –1
Option 3: 0
Option 4: 6
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Correct Answer: –6
Solution : Given: $f(x)=x^3+2x^2-5x+k=0$ is divisible by $x+1$. So, $ x^3+2x^2-5x+k=0$ when $x=-1$ ⇒ $ (-1)^3+2(-1)^2-5(-1)+k=0$ ⇒ $-1+2+5+k=0$ ⇒ $ k = -6$ Hence, the correct answer is –6.
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Question : If $4(2x+3)>5-x$ and $5x-3(2x-7)>3x-1,$ then $x$ can take which of the following values?
Option 1: 6
Option 3: 5
Option 4: –6
Question : If $2x-2(x-2)<5-x>-2x+2$, then the value of $x$ is:
Option 1: 0
Option 2: 2
Option 3: 3
Option 4: –4
Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Option 1: 2
Option 3: 1
Option 4: 0
Question : If $4(x+5)-3>6-4x\geq x-5$, then the value of $x$ is:
Option 1: –2
Option 4: 4
Question : If $x^{2}+\frac{1}{x^{2}}=1$, then, what is the value of $x^{48}+x^{42}+x^{36}+x^{30}+x^{24}+x^{18}+x^{12}+x^{6}+1$?
Option 1: – 9
Option 2: 0
Option 4: 9
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