Question : If PT is a tangent at T to a circle whose centre is O and OP = 17 cm and OT = 8 cm, find the length of the tangent segment PT.
Option 1: 13 cm
Option 2: 14 cm
Option 3: 16 cm
Option 4: 15 cm
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Correct Answer: 15 cm
Solution : Let the tangent drawn from point P to the circle meet it at point T. Let O be the centre of the circle Given, OP = 17 cm and OT = 8 cm We know that tangent makes a right angle with radius at the point of contact. So, $\angle$ OTP = 90° Using Pythagoras theorem in triangle OTP, OP2 = OT2 + PT2 ⇒ 172 = 82 + PT2 ⇒ PT = 15 cm Hence, the correct answer is 15 cm.
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Question : Let O be the centre of the circle and P be a point outside the circle. If PAB is a secant of the circle which cuts the circle at A and B and PT is the tangent drawn from P, then find the length of PT, if PA = 3 cm and AB = 9 cm.
Option 1: $3 \sqrt{3} \mathrm{~cm}$
Option 2: $4 \sqrt{3} \mathrm{~cm}$
Option 3: 6 cm
Option 4: 8 cm
Question : O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
Option 1: 26 cm
Option 2: 52 cm
Option 3: 13 cm
Question : Two circles touch each other externally. The radius of the first circle with centre O is 12 cm. Radius of the second circle with centre A is 8 cm. Find the length of their common tangent BC.
Option 1: $6 \sqrt{6} \mathrm{~cm}$
Option 2: $8 \sqrt{3} \mathrm{~cm}$
Option 3: $8 \sqrt{2} \mathrm{~cm}$
Option 4: $8 \sqrt{6} \mathrm{~cm}$
Question : The length of the common chord of two circles of radii 15 cm and 13 cm, whose centres are 14 cm apart, is:
Option 1: 14 cm
Option 2: 12 cm
Option 3: 15 cm
Option 4: 24 cm
Question : In a circle, a 14 cm long chord is 24 cm from the centre of the circle. Find the length of the radius of the circle.
Option 1: 30 cm
Option 2: 25 cm
Option 3: 50 cm
Option 4: 27 cm
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