Question : If the 7-digit number $x$468$y$05 is divisible by 11, then what is the value of ($x$ + $y$)?
Option 1: 12
Option 2: 14
Option 3: 8
Option 4: 10
Correct Answer: 12
Solution : Given: If the 7-digit number $x468y05$ is divisible by 11. Then, Sum of the digits at odd places – Sum of the digits at even places = 0 or, 11 Now, Sum of the digits at odd places – Sum of the digits at even places = 11 $\Rightarrow (x\ +\ 6\ +\ y\ +\ 5)\ -\ (0\ +\ 4\ +\ 8)\ =\ 11$ $\Rightarrow x\ +\ y\ +\ 11\ - 12\ =\ 11$ $\therefore x\ +\ y\ =\ 12$ So, the maximum value of $x\ +\ y$ is 12. Hence, the correct answer is 12.
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Question : If the six-digit number 5x2y6z is divisible by 7, 11 and 13, then the value of $(x-y+3 z)$ is:
Option 1: 7
Option 2: 4
Option 3: 0
Option 4: 9
Question : If a nine-digit number 785$x$3678$y$ is divisible by 72, then the value of ($x$ + $y$) is:
Option 1: 20
Option 2: 12
Option 3: 10
Option 4: 5
Question : If the six-digit number 479xyz is exactly divisible by 7, 11, and 13, then {(y + z) ÷ x} is equal to:
Option 1: $4$
Option 2: $\frac{11}{9}$
Option 3: $\frac{7}{13}$
Option 4: $\frac{13}{7}$
Question : If $x^4+x^2 y^2+y^4=133$ and $x^2-x y+y^2=7$, then what is the value of $xy$?
Option 1: 8
Option 3: 4
Option 4: 6
Question : If the 9-digit number $72 x 8431y 4$ is divisible by 36, what is the value of $(\frac{x}{y}-\frac{y}{x})$ for the smallest possible value of $y$, given that $x$ and $y$ are natural numbers?
Option 1: $1 \frac{5}{7}$
Option 2: $2 \frac{1}{10}$
Option 3: $1 \frac{2}{5}$
Option 4: $2 \frac{9}{10}$
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