Question : If the diagonals of a rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the rhombus?
Option 1: 32 cm
Option 2: 64 cm
Option 3: 34 cm
Option 4: 68 cm
Correct Answer: 68 cm
Solution : The diagonals of a rhombus are 16 cm and 30 cm. We know diagonals perpendicularly bisect each other in a rhombus. Side of a rhombus = $\sqrt{(\frac{\text{Diagonal_1}}{2})^2 + (\frac { \text{Diagonal_2}}{2})^2}$ ⇒ Side of rhombus = $\sqrt{(\frac{16}{2})^{2}+ (\frac{30}{2})^{2}}$ ⇒ Side = $\sqrt{82+152} = \sqrt{289} = 17$ cm $\therefore$ Perimeter = 4 × 17 = 68 cm (Since all sides are equal in a rhombus) Hence, the correct answer is 68 cm.
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Question : If the diagonals of a Rhombus are 16 cm and 30 cm. What is the perimeter (in cm) of the Rhombus?
Option 1: 32
Option 2: 64
Option 3: 34
Option 4: 68
Question : If the diagonals of a Rhombus are 12 cm and 16 cm, then what is the perimeter (in cm) of the Rhombus?
Option 1: 20 cm
Option 2: 40 cm
Option 3: 60 cm
Option 4: 80 cm
Question : If the perimeter of a rhombus is 40 cm and one of its diagonals is 16 cm, what is the area (in cm2) of the rhombus?
Option 1: 72
Option 2: 48
Option 3: 96
Option 4: 192
Question : If the perimeter of a rhombus is 80 cm and one of its diagonals is 24 cm, then what is the area (in cm2) of the rhombus?
Option 1: 218
Option 2: 192
Option 3: 384
Option 4: 768
Question : Find the area of a rhombus if the perimeter of the rhombus is 52 cm, and one of its diagonals is 10 cm long.
Option 1: 120 cm2
Option 2: 164 cm2
Option 3: 160 cm2
Option 4: 144 cm2
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