Question : If the radius of a sphere increases by 10%, what would be the change in the surface area of the sphere?
Option 1: 20%
Option 2: 21%
Option 3: 31%
Option 4: 25%
Correct Answer: 21%
Solution : The surface area ($A$) of a sphere is $4\pi r^2$, where $r$ is the radius of the sphere. If the radius increases by 10%, the new radius is $(r+0.1r) = 1.1r$ The new surface area of the sphere is then $= 4\pi (1.1r)^2 = 4\pi \times 1.21r^2 = 1.21 \times 4\pi r^2 = 1.21A$ So, the change in surface area $=\frac{1.21A-A}{A}×100 = 21$% Hence, the correct answer is 21%.
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Question : If the radius of a sphere is doubled, then its surface area will be increased by:
Option 1: 100%
Option 2: 200%
Option 3: 300%
Option 4: 400%
Question : When the radius of a sphere is increased by 5 cm, its surface area increases by 704 cm2. The diameter of the original sphere is _________. (Take $\pi=22 / 7$ )
Option 1: 8.2 cm
Option 2: 6.8 cm
Option 3: 5.2 cm
Option 4: 6.2 cm
Question : Which of the following statements is not correct?
Option 1: For a given radius and height, a right circular cone has a lesser volume than a right circular cylinder.
Option 2: If the side of a cube is increased by 10%, the volume will increase by 33.1%.
Option 3: If the radius of a sphere is increased by 20%, the surface area will increase by 40%.
Option 4: Cutting a sphere into 2 parts does not change the total volume.
Question : The radius of a hemisphere is twice that of a sphere. What is the ratio of the total surface area of the hemisphere and sphere?
Option 1: 3 : 1
Option 2: 12 : 1
Option 3: 4 : 1
Option 4: 6 : 1
Question : If the radius of a hemispherical balloon increases from 4 cm to 7 cm as air is pumped into it, find the ratio of the surface area of the new balloon to its original.
Option 1: 16 : 21
Option 2: 49 : 16
Option 3: 20 : 49
Option 4: 21 : 12
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